K= 2m-x/ x solve for x

What is the constant of proportionality in this graph?

lana [24]

Answer:

one half or 1/2

Step-by-step explanation:

do your rise over your run on the graph.

7 0

4 years ago

The nth term of 50, 80, 110 is...

Olenka [21]

Answer:

$a_n=50+(n-1)30$

Step-by-step explanation:

Given series is,

50,80,110....

First term, a = 50

Common difference, d = 80-50 = 30

We need to find the nth term of the given sequence.

The nth term of an AP is given by :

$a_n=a+(n-1)d$

Put a = 50 and d = 30 in the above formula

$a_n=50+(n-1)30$

Hence, the nth term of the sequence is $a_n=50+(n-1)30$ .

5 0

3 years ago

It is claimed that the proportion of people who favor the use of oxygenated fuels year around to reduce air pollution is 60%. A

attashe74 [19]

Answer:

Conclusion is that there is sufficient evidence to reject the claim that the proportion of people who favor the use of oxygenated fuels year around to reduce air pollution is 60%.

Step-by-step explanation:

We are given;

Population proportion; p = 60% = 0.6

Sample mean: x¯ = 315

Sample size; n = 500

Significance level = 0.09

Defining the hypothesis, we have;

Null Hypothesis; H0: p = 0.6

Alternative hypothesis; Ha: p > 0.6

z-score formula in this case is;

z = (x¯ - np)/√(np(1 - p))

Plugging in the relevant values;

z = (315 - (500 × 0.6))/√(500 × 0.6(1 - 0.6))

z = 1.72

From z-distribution table, the p-value at z = 1.72 is;

1 - P(Z ≤ z-score)

This gives:

p-value = 1 - 0.95728 = 0.04272

Thus p-value is less than the significance level of 0.09, thus we will reject the null hypothesis and conclude that there is sufficient evidence to reject the claim that the proportion of people who favor the use of oxygenated fuels year around to reduce air pollution is 60%.

6 0

3 years ago

The ratio of North American butterflies to South American butterflies at a butterfly park is 5:3. The ratio of South American bu

Natalija [7]

Answer: There are 12 European butterflies.

Step-by-step explanation:

Let be "s" the number of South American butterflies at the butterfly park.

Since the ratio of North American butterflies to South American butterflies at a butterfly park is 5:3 and the number of North American butterflies at the butterfly park is 30, you can write the folllowing proportion:

$\frac{5}{3}=\frac{30}{s}$

Solving for "s", you get:

$(s)(\frac{5}{3})=30\\\\s=(30)(\frac{3}{5})\\\\s=18$

Let be "e" the number of European butterflies at the butterfly park.

Knowing that the ratio of South American butterflies to European butterflies at the butterfly park is 3:2, and since there are 18 South American butterflies, you can write the following proportion:

$\frac{3}{2}=\frac{18}{e}$

Solving for "e", you get:

$(e)(\frac{3}{2})=18\\\\e=(18)(\frac{2}{3})\\\\e=12$

4 0

4 years ago

In 2003, the price of a certain automobile was approximately $32,000 with a depreciation of $1,740 per year. After how many year

IRINA_888 [86]

Answer:

The correct answer is 5 years i.e. 2008.

Step-by-step explanation:

Price of the automobile in 2003 is $32000.

Depreciation per year is given by $1740.

Therefore let the car value is depreciated for t number of years.

Value depreciated for t years is given by $ (1740t).

The final value of the car after t years is given to be $23300.

Thus the equation is given by 32000 - 1740t = 23300.

⇒ 1740t = 32000 - 23300

⇒ 1740t = 8700

⇒ t = 5

Thus after 5 years the value of the car is $23300.

Thus in 2008 the depreciated price of the car would be $23300.

7 0

4 years ago