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ycow [4]
3 years ago
5

Help me please Thanks

Mathematics
1 answer:
Klio2033 [76]3 years ago
4 0
The answer is 1;3 because if you simplified 2;6 you get 1;3 so the answer to that is
a: 1;3
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What is the slope G(8,1) & H(8,-6).
Gennadij [26K]
M=slope=(y2-y1)/(x2-x1)=(-6-1)/(8-8)=-7/0 which is technically undefined.  This is just a vertical line namely:

x=8  (you can think of a vertical line as having infinite slope)
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Can somebody help solve either of these?
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First one:
The circumference of the whole circle is (2π x the radius), 
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Second one:
The area of the whole circle is (π x the radius²), and
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2 years ago
At least how many hours of sleep do students ages seven to twelve need per night
kozerog [31]

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10

Step-by-step explanation:

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The length of a rectangle is 3 1/6 cm longer than the width. The perimeter of the rectangle is 15 1/3 cm. What are the width and
sammy [17]

Answer:

Length:3 1/6

Width:4

Step-by-step explanation:

4 0
2 years ago
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WILL GIVE BRAINLIEST A rocket is launched vertically from the ground with an initial velocity of 64. Write a quadratic function
tiny-mole [99]

Answer:

h=64t-4.9t^{2}

Please refer to the attached graph.

Step-by-step explanation:

Given that

Initial velocity of rocket = 64 and is launched vertically.

To find:

Quadratic equation in time to represent the height of rocket in feet.

Solution:

Unit of initial velocity is not given in the question statement, let the velocity be in feet/second only.

Initial velocity, u  = 64 feet/s

The acceleration will be = -g because it is going opposite to gravitational force so it will be negative acceleration motion (speed will be decreasing) so -g will be the acceleration.

Formula for distance traveled is given as:

s=ut+\dfrac{1}{2}at^2

Here Let us represent s by 'h'

a = -g = 9.8 m/s^2

Let us put the known values in the formula:

h=64t+\dfrac{1}{2}(-9.8)t^2\\\Rightarrow h =64t-4.9t^2

It is a quadratic equation, the equation represents the graph of a parabola.

Please refer to the attached graph.

Value of height is 0 at 0 second and ~13 seconds

6 0
3 years ago
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