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3 years ago

1. Mr. Hurst's house increased in value to $185,400 one year after he bought

Mathematics

1 answer:

katovenus [111]3 years ago

8 0

Answer:

Step-by-step explanation:

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I need help ? which linear function is represented by the graph?

PilotLPTM [1.2K]

<h3>Answer: f(x) = (-1/2)x+1, choice B</h3>

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Explanation:

The diagonal line passes through 1 on the vertical y axis. So the y intercept is b = 1. This means the location of the y intercept is (0,1).

Start at (0,1) and move down 1 and to the right 2 to arrive at (2,0). This is another point on the diagonal line. The motion of "down 1 and right 2" is effectively the slope

slope = rise/run = -1/2

rise = -1, run = 2

The rise being negative means we have gone downhill as we move to the right.

With m = -1/2 as the slope and b = 1 as the y intercept, we go from y = mx+b to y = (-1/2)x+1

The last thing to do is replace y with f(x) to get f(x) = (-1/2)x+1 as the final answer.

4 0

3 years ago

Read 2 more answers

9/10 divided by 3/5<br> please helppp

Westkost [7]

Answer:

=1.5

Step-by-step explanation:

3 0

3 years ago

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

3 years ago

Explain in words how you would evaluate the expression 5.1 + q ÷ 3.4 for q = 28.9

statuscvo [17]

You would plug in twenty eight point nine to the q. So it would be five point one plus twenty eight point nine divided by three point four, which equals thirteen point six.

4 0

3 years ago

Read 2 more answers

The inner dimensions of an in-ground swimming pool are: width = 13.0 ft, length = 18.0 ft, and depth = 9.0 ft. The pool walls an

lawyer [7]

The answer: a) 386208

And you can see the method solution

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4 0

3 years ago