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Readme [11.4K]
3 years ago
11

Plz plz help me

Mathematics
1 answer:
eduard3 years ago
4 0

Answer:

  • ...  construction of parallel lines (parallel to AB through C)
  • ... width to IJ

Step-by-step explanation:

Construction of parallel lines is accomplished by copying an angle. Here, the steps shown will result in copying the angle IDJ if the distance IJ is marked on the arc through k, then a line drawn through C and the point just marked.

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So difficult!!! Someone help
Naya [18.7K]
When two lines cross like this, sum of measures of opposite angles is 180.
this means that:
measure angle AEC + measure angle BED = 180
4x-40 + x+50 = 180
5x +10 = 180
5x = 170
x = 34
therefore:
measure angle AEC = 4x-40 = 4(34)-40 = 96
measure angle BED = x+50 = 34+50 = 84
5 0
4 years ago
For every how many degrees will a pentagon have rotational symmetry?
igor_vitrenko [27]
A. 72 degrees (i hope this helped)
7 0
3 years ago
Read 2 more answers
Helphelphelpjehkejjosndidnkdndjdndjfnkdndosndjjd
Hoochie [10]
A'(1,-2)
B'(1,-3)
C'(-1,-3)
D'(-1,-2)
8 0
4 years ago
Solve the 3D figure Rectangle is A=BH<br> Triangle is A=1/2BH
IceJOKER [234]

Answer:

The area of the 3d figure

Step-by-step explanation:

the area of the one of triangle is 8.7

and the reactangle is 5 x 7 = 35

and the big one is 10 x 7 = 70

so 8.7 + 8.7 + 35 + 35 + 70 = 157.4

7 0
2 years ago
If all city buses carry the same number of passengers, what is the least number of buses needed to carry 710 passengers? 5 10 11
noname [10]

The least number of buses needed to carry 710 passengers is 5.

Option A)5 is the correct answer.

<h3>What is the least number of buses needed to carry 710 passengers? </h3>

Given that;

  • Number of passengers n = 710
  • Least number of buses need B = ?

To get the least number of buses, we say;

Number of buses B = 710 ÷ 150

Number of buses B = 4.7 ≈ 5

The least number of buses needed to carry 710 passengers is 5.

Option A)5 is the correct answer.

Learn to solve more word problems here: brainly.com/question/2610134

#SPJ4

5 0
2 years ago
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