Answer:
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs is the answer.
Step-by-step explanation:
given that Ty and Gajge are football players.
Carries is 15 for both and average is the same 4 for both.
But on scrutiny we find that maximum and minimum and 6 and 2 for Ty.
Hence range for Ty = 6-2 =4 (2 runs on eithre side of mean)
But for Gajge, highest is 19 and lowest is 2.
i.e. range = 19-2 =17 very much higher than that of Ty
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.
<span>sqrt(pow(length, 2) + pow(width, 2))
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Answer:
8 pieces of string
Step-by-step explanation:
Given that :
Total yards of string = 4
Length in yd of each string = 1/2 yards
Number of pieces of string Ms. Cole has :
Total. Yards / length in yard of each string
4 / (1/2)
4 * (2 /1)
= 8/1
= 8 pieces of string.
I thank it is B you have to add all the tickets and times that by the the amount of money
