Question

What’s the sum of the measures of the exterior angles of a 53-gon?

Answer 1

Option B

The sum of the measures of the exterior angles of a 53 - gon is 360 degrees

Solution:

The formula for sum of exterior angles "n" is:

$N = 180n-180(n-2)$

Distribute 180

$N = 180n - 180n + 360\\\\N = 360$

Therefore, sum of measure of exterior angles is 360 degrees

Sum of the measures of all the exterior angles of any polygon, irrespective of its number of sides is always 360 degrees

Thus, in a 53 gon, sum of measure of exterior angles is 360 degrees