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Mariulka [41]
3 years ago
14

Fill in the blank to make this expression a perfect square x^2 + 2x + blank

Mathematics
1 answer:
Inessa05 [86]3 years ago
7 0

Answer:

x^2+2x+1

Step-by-step explanation:

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6. In the equation Q – 12 = 89, what is the value of Q?
muminat
Q - 12 = 89
Q = 89 + 12
Q = 101
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An equation in two variables is shown below.
Romashka [77]

Answer:

mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

Step-by-step explanation:

             mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmkmmmmmmmmmmmmmmmmmmmmmmk

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4 years ago
3x=12<br> Please answer did
Assoli18 [71]

Answer:

x=4

Step-by-step explanation:

divide both sides by 3

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3 years ago
A 2.0 kg cart moving right at 5.0 on a frictionless track collides with a 3.0 kg cart initially at rest. The 2.0 kg
Wewaii [24]

final speed of the 3.0 kg cart is 2.67 m/s .

<u>Step-by-step explanation:</u>

Here we have , A 2.0 kg cart moving right at 5.0 on a friction less track collides with a 3.0 kg cart initially at rest. The 2.0 kg  cart has a final speed of 1.0 to the left. We will use law of conservation of momentum: For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

m_1(v_1)+m_2(v_2) =m_1(v_3)+m_2(v_4)

⇒ m_1(v_1)+m_2(v_2) =m_1(v_3)+m_2(v_4)

⇒ 2(5)+3(0) =2(1)+3(v_4)

⇒ 10 =2+3(v_4)

⇒ 3(v_4) = 8

⇒ (v_4) = \frac{8}{3}

⇒ (v_4) = 2.67

Therefore, final speed of the 3.0 kg cart is 2.67 m/s .

4 0
4 years ago
The coordinates of the vertices of △JKL are J(3, 4), K(3, 1) , and L(1, 1) . The coordinates of the vertices of △J′K′L′ are J′(−
timurjin [86]

The <em><u>correct answer</u></em> is:

A 180° rotation followed by a translation 1 unit down.

Explanation:

The points are mapped as follows:

J(3, 4)→J'(-3, -5)

K(3, 1)→K'(-3, -2)

L(1, 1)→L'(-1, -2)

A 180° rotation maps a point (x, y) to (-x, -y).  This would map

J(3, 4)→(-3, -4)

K(3, 1)→(-3, -1)

L(1, 1)→(-1, -1)

The difference between these points and the image points are that each y-coordinate of the image is 1 lower than these.  This means a translation 1 unit down would result in the image points.

7 0
3 years ago
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