Q - 12 = 89
Q = 89 + 12
Q = 101
Answer:
mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
Step-by-step explanation:
mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmkmmmmmmmmmmmmmmmmmmmmmmk
Answer:
x=4
Step-by-step explanation:
divide both sides by 3
final speed of the 3.0 kg cart is 2.67 m/s .
<u>Step-by-step explanation:</u>
Here we have , A 2.0 kg cart moving right at 5.0 on a friction less track collides with a 3.0 kg cart initially at rest. The 2.0 kg cart has a final speed of 1.0 to the left. We will use law of conservation of momentum: For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

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Therefore, final speed of the 3.0 kg cart is 2.67 m/s .
The <em><u>correct answer</u></em> is:
A 180° rotation followed by a translation 1 unit down.
Explanation:
The points are mapped as follows:
J(3, 4)→J'(-3, -5)
K(3, 1)→K'(-3, -2)
L(1, 1)→L'(-1, -2)
A 180° rotation maps a point (x, y) to (-x, -y). This would map
J(3, 4)→(-3, -4)
K(3, 1)→(-3, -1)
L(1, 1)→(-1, -1)
The difference between these points and the image points are that each y-coordinate of the image is 1 lower than these. This means a translation 1 unit down would result in the image points.