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Vikentia [17]
3 years ago
10

After 3 minutes, a submarine had descended to −320 feet. After 8 minutes, the submarine had descended to −420 feet. Assuming a l

inear function, write an equation in the form d(t)=mt+b that shows the depth, d(t), after t minutes
Mathematics
1 answer:
LiRa [457]3 years ago
7 0

Answer:

d(t) = -20t - 260

Step-by-step explanation:

The depth function is:

d(t) = mt + b

After 3 minutes, a submarine had descended to −320 feet.

This means that d(3) = -320. So

d(t) = mt + b

-320 = 3m + b

After 8 minutes, the submarine had descended to −420 feet.

This means that d(8) = -420. So

d(t) = mt + b

-420 = 8m + b

From the first equation:

b = -320 - 3m

So

-420 = 8m + b

-420 = 8m - 320 - 3m

5m = -100

m = \frac{-100}{5}

m = -20

And

b = -320 - 3*(-20) = -260

So

d(t) = -20t - 260

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What is the answer to -104=8x how do you find what x is
dybincka [34]
8x = -104 (I like to flip mine around like this, but it doesn't matter).
Now, you subtract 8 from both sides because you are doing the inverse.
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Hope this helps!
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3 years ago
If there is an open circle on a number on a number line, is that number included in the inequality
natta225 [31]
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3 years ago
4 1/3 - 1 2/3 how to solve this please
8_murik_8 [283]

Answer:

2\frac{2}{3}

Step-by-step explanation:

1) Convert 4\frac{1}{3} to improper fraction. Use this rule: a\frac{b}{c} =\frac{ac+b}{c}.

\frac{4\times3+1}{3} -1\frac{2}{3}

2) Simplify 4 * 3 to 12.

\frac{12+1}{3}

3) Simplify 12 + 1 to 13.

\frac{13}{3} -1\frac{2}{3}

4) Convert 1\frac{2}{3}   to improper fraction. Use this rule: a\frac{b}{c} =\frac{ac+b}{c}.

\frac{13}{3} -\frac{1\times3+2}{3}

5) Simplify 1 * 3 to 3.

\frac{13}{3} -\frac{3+2}{3}

6) Simplify 3 + 2 to 5.

\frac{13}{3} -\frac{5}{3}

7) Join the denominators.

\frac{13-5}{3}

8) Simplify.

\frac{8}{3}

9) Convert to mixed fraction.

2\frac{2}{3}

(Decimal Form: 2.666667)

Thank you,
Eddie

3 0
2 years ago
What is the length of RS.
Natali [406]

Consider, in ΔRPQ,

RP = R (Radius of larger circle)

PQ = r (radius of smaller circle)

We have to find, RQ, by Pythagoras theorem,

RP² = PQ²+RQ²

R² = r²+RQ²

RQ² = R²-r²

RQ = √(R²-r²

Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ

RS = 2√(R²-r²)

5 0
3 years ago
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