When reflecting across the Y axis, the Y values remain the same.
Now if you were reflecting across Y = 0, the x values would just be inverse ( opposite signs).
So this triangle if reflected across Y = 0 the new vertices would be (4,4) (2,3) and (5,2)
Now since the reflection line is y = -1, which is a one unit shift to the left of y = 0, subtract 1 unit from each X value.
The locations are now: A'(3,4), B'(1,3) and C'(4,2)
Answer:
0
Step-by-step explanation:
(-4,0) and (3,2)
m1=(2-0)/(3+4)=2/7
y=2/7x+b1, using point (-4,0) to find b1 (substitute x=-4 and y=0 in the form)
0=2/7*(-4)+b1 ⇒ b1= 8/7
-----
(-3,2) and (4,0)
m2=(0-2)/(4+3)= -2/7
y= -2/7x+b2, using point (4,0) to find b2 (substitute x=4 and y=0 in the form)
0= -2/7*4+b2 ⇒ b2=8/7
----
m1b2+m2b1= 2/7*8/7 -2/7*8/7=0
Answer:
i think b or d
Step-by-step explanation:
Answer: x is, 2 6 8 10 20-- i think
Step-by-step explanation: y is, 2 3 4 6 10
The axis of symmetry is given by the line x = a (where a is equivalent to the x-value of the turning point of the parabola) and can be viewed as the line about which the parabola is symmetric; in this case, the parabola has an axis of symmetry of x = 2, thus the answer is B
