Given :
A 136 foot tall cell phone tower casts a 79.9 foot shadow.
To Find :
The shadow length for a nearby 40 foot telephone pole .
Solution :
We know , the ratio of height and shadow , will be same for every object .
Let , length of shadow of pole is x .
So ,
![\dfrac{79.9}{136}=\dfrac{x}{40}\\\\x=\dfrac{79.9\times 40}{136}\ foot\\\\x=23.5\ foot](https://tex.z-dn.net/?f=%5Cdfrac%7B79.9%7D%7B136%7D%3D%5Cdfrac%7Bx%7D%7B40%7D%5C%5C%5C%5Cx%3D%5Cdfrac%7B79.9%5Ctimes%2040%7D%7B136%7D%5C%20foot%5C%5C%5C%5Cx%3D23.5%5C%20foot)
Therefore , the length of shadow of tower is 23.5 foot .
Hence , this is the required solution .
Answer:
<u><em>6</em></u>
Step-by-step explanation:
Hey there) The formula of your line is:
![-2=2k+b\\2=-6k+b\\=>4=-8k\\k=-0.5\\=> b=-2+1=-1\\=>y=-\dfrac{1}{2}x-1\\](https://tex.z-dn.net/?f=-2%3D2k%2Bb%5C%5C2%3D-6k%2Bb%5C%5C%3D%3E4%3D-8k%5C%5Ck%3D-0.5%5C%5C%3D%3E%20b%3D-2%2B1%3D-1%5C%5C%3D%3Ey%3D-%5Cdfrac%7B1%7D%7B2%7Dx-1%5C%5C)
If point has y=-4, then:
![-4=-\dfrac{1}{2}a-1\\4=\dfrac{1}{2}a+1\\a=6](https://tex.z-dn.net/?f=-4%3D-%5Cdfrac%7B1%7D%7B2%7Da-1%5C%5C4%3D%5Cdfrac%7B1%7D%7B2%7Da%2B1%5C%5Ca%3D6)
Hope this helps) Have a nice day/night :)
Answer:
8. 0
9. undefined
Step-by-step explanation:
8. 0
> because the y variable is the same for all x-values, this is a horizontal line. Horizontal lines have a slope of 0.
> <em>Thinking of slope as rise over run: we will always rise 0, and run __ from any two points--0 divided by any number is always 0</em>
9. undefined
> because the x variable is always the same, no matter what y variable we graph, we will have the same outcome. So, this would look like a straight line, which have an undefined slope.
> <em>If you think of a slope as rise / run; if you go from any two points, there will be a 0 in the denominator--which is undefined</em>
<em />
<em />
hope this helps!! have a lovely day :)
Answer:
![y=43](https://tex.z-dn.net/?f=y%3D43)
Step-by-step explanation:
![y=2(90-46)/2](https://tex.z-dn.net/?f=y%3D2%2890-46%29%2F2)
![y=43](https://tex.z-dn.net/?f=y%3D43)
<u>------------------------</u>
<u>OAmalOHopeO</u>
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