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mina [271]
3 years ago
8

Roger wants to give semantic meaning to the contact information, which is at the bottom of the web page. To do this

Computers and Technology
1 answer:
sdas [7]3 years ago
7 0

Answer:

The answer is "Option b"

Explanation:

In the footer element, the roger uses parent element as the contact information because defined in critical analysis, in which critical thought is knowledge, in which it is widely applicable to life. It just implies that, logically and rationally, you evaluate details, its weaknesses, and strengths, and other options were wrong that can be described as follows:

  • Option a and Option d is not correct because that doesn't use this information section.
  • In option c, It is also not correct because it is related to the child.
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is a specific system for gathering information from a single group of respondents by continuously monitoring the advertising, pr
irga5000 [103]

Answer:

The answer is "Scanner based research".

Explanation:

A scanner focused testing method allows advertisers to track the exposure and response of a consumer panel to variables like ads, promotions, store displays, packaging, and quality.  

  • This technique is used to buy is considered a total answer because the received outcomes are not conditional on test survey results.
  • The purpose of this method is used to support the framework for marketing decisions.
3 0
4 years ago
COMPUTER ORGANIZATION &amp; ARCHITECTURE I question 3<br> need correct the answers to all
evablogger [386]
Is there anything about this question?
4 0
3 years ago
Which of the following statements is true?
Sonbull [250]

Answer:

C

Explanation:

Predicate methods typically test a condition and do not modify the object on which they're called.

6 0
3 years ago
An enhancement to a computer accelerates some mode of execution by a factor of 10. The enhanced mode is used 50% of the time, me
Ann [662]

Answer:

The answer is "5.5 and 90.90%"

Explanation:

For point 1:

To calculate the speed from fast mode, its run time without enhancement should be worked out. Designers are aware of which two selves are implicated throughout the accelerated project planning: the empty (50 \%) and the increased stages (50 \%).

Although not enhanced, this would take almost as long (50 \%) and for the combine to give phase; even so, the increased phase would've been 10 times longer, as well as 500 \%. Thus the corresponding total speed without enhancement is =50\% + 500\% = 550\%.

Its overall speed is:

=\frac{\text{Accelerated runtime}}{ \text{accelerated  runtime}} = \frac{550 \%}{ 100 \%}= 5.5

For point 2:

We re-connect these figures in Amdahl's Law throughout order to identify how long it would take for both the initial implementation:

\text{Vectorized fraction}= \frac{\text{Overall velocity}\times \text{Accelerated acceleration}-\text{Accelerated acceleration}}{\text{Overall acceleration} \times \text{Accelerated acceleration}-\text{Overall acceleration}}

                              = \frac{5.5  \times 10 -10 }{ 5.5 \times 10 - 5.5}\\\\=\frac{45}{49.5}\\\\=0.9090\\\\=90.90\%

5 0
3 years ago
Coupon collector is a classic statistic problem with many practical applications. The problem is to pick objects from a set of o
ahrayia [7]

Answer:

Here is the JAVA program:

public class Main {  //class name

public static void main(String[] args) {   //start of main method

//sets all boolean type variables spades, hearts diamonds and clubs to false initially

   boolean spades = false;  

   boolean hearts = false;

   boolean diamonds = false;

   boolean clubs = false;  

   String[] deck = new String[4];  //to store card sequence

   int index = 0;  //to store index position

   int NoOfPicks = 0;  //to store number of picks (picks count)

   while (!spades || !hearts || !diamonds || !clubs) {   //loop starts

       String card = printCard(getRandomCard());  //calls printCard method by passing getRandomCard method as argument to it to get the card

       NoOfPicks++;   //adds 1 to pick count

       if (card.contains("Spades") && !spades) {  //if that random card is a card of Spades and spades is not false

           deck[index++] = card;  //add that card to the index position of deck

           spades = true;  //sets spades to true

       } else if (card.contains("Hearts") && !hearts) {  //if that random card is a card of Hearts and hearts is not false

           deck[index++] = card;  

           hearts = true;   //sets hearts to true

       } else if (card.contains("Diamond") && !diamonds) {  //if that random card is a card of Diamond and diamonds is not false

           deck[index++] = card;

           diamonds = true;  //sets diamonds to true

       } else if (card.contains("Clubs") && !clubs) {  if that random card is a card of Clubs and clubs is not false

           deck[index++] = card;

           clubs = true;         }     }   //sets clubs to true

   for (int i = 0; i < deck.length; i++) {  //iterates through the deck i.e. card sequence array

       System.out.println(deck[i]);     }  //prints the card number in deck

   System.out.println("Number of picks: " + NoOfPicks);  }   //prints number of picks

public static int getRandomCard() {  //gets random card

   return (int) (Math.random() * 52); }   //generates random numbers of 52 range

public static String printCard(int cardNo) {   //displays rank number and suit

   String[] suits = { "Spades", "Hearts", "Diamonds", "Clubs", };  //array of suits

   String[] rankCards = { "Ace", "2", "3", "4", "5", "6", "7", "8", "9", "10",

           "Jack", "Queen", "King" };   //array of rank

  int suitNo = cardNo / 13;  //divides card number by 13 and stores to suitNo

 int rankNo = cardNo % 13;   //takes modulo of card number and 13 and store it to rankNo

   return rankCards[rankNo] + " of " + suits[suitNo];  }}  //returns rankCard at rankNo index and suits at suitNo index

Explanation:

The program is explained in the comments attached with each line of code. The screenshot of the program along with its output is attached.

8 0
3 years ago
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