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4 years ago

I’m sorry I don’t understand these

Mathematics

1 answer:

olga2289 [7]4 years ago

5 0

Answer:

1)positive slope

2) 6

3) w = 12t

4) $slope = \frac{2}{-5}$

Step-by-step explanation:

1) The slope of line is given by tan(∅), Where ∅ is the angle of line with positive x axis. Here The value of ∅ is between 0 and 90 degrees, so tan(∅) is positive, which means slope is positive.

2) It is given that y=24 and x=4, inserting in the given equation, we get $k = \frac{24}{4} = 6$ .

3) The earning rate is given by $12 per hour. If the number of working hours are t, then the total earnings are $w= (12)(t)$ .

4)The slope is given by , $m = \frac{y2-y1}{x2-x1}$ , where (x1,y1) and (x2,y2) are endpoints. Thus, here above the slope is given by,

$m = \frac{3-1}{1-6} = \frac{2}{-5}$

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Dani has only of a cup of baking mix. She needs of a cup for one batch of muffins. Which solution method shows how much of a bat

anastassius [24]

Step-by-step explanation:

Dani have to take 2 of a batch muffins

5 0

3 years ago

Someone help me out on these 2 geometry questions, ASAP!!! “Complete the proofs”

vodomira [7]

Question 11

1) $\overline{BA} \cong \overline{FA}$ , $\angle 1 \cong \angle 2$ (given)

2) $\angle A \cong \angle A$ (reflexive property)

3) $\triangle AEB \cong \triangle ACF$ (ASA)

4) $\overline{AC} \cong \overline{AE}$ (CPCTC)

Question 12

1) Isosceles $\triangle ACD$ with $\overline{AC} \cong \overline{AD}$ , $\overline{BC} \cong \overline{ED}$ (given)

2) $\angle ACD \cong \angle ADC$ (angles opposite congruent sides in a triangle are congruent)

3) $\angle ACB$ and $\angle ACD$ are supplementary. $\angle ADC$ and $\angle ADE$ are supplementary (angles that form a linear pair are supplementary)

4) $\angle ACB \cong \angle ADE$ (supplements of congruent angles are congruent)

5) $\triangle ABC \cong \triangle AED$ (SAS)

6) $\overline{AB} \cong \overline{AE}$ (CPCTC)

7) $\triangle ABE$ is an isosceles triangle (a triangle with two congruent sides is isosceles)

Note: I changed the names of the segments in Question 11 because of the word filter.

5 0

2 years ago

A rock is thrown upward from a bridge that is 57 feet above a road. The rock reaches its maximum height above the road 0.76 seco

bekas [8.4K]

answer:

$f(t) = -9.9788169(t -0.76)^2 +57$

Step-by-step explanation:

On this question we see that we are given two points on a certain graph that has a maximum point at 57 feet and in 0.76 seconds after it is thrown, we know can say this point is a turning point of a graph of the rock that is thrown as we are told that the function f determines the rocks height above the road (in feet) in terms of the number of seconds t since the rock was thrown therefore this turning point coordinate can be written as (0.76, 57) as we are told the height represents y and x is represented by time in seconds. We are further given another point on the graph where the height is now 0 feet on the road then at this point its after 3.15 seconds in which the rock is thrown in therefore this coordinate is (3.15,0).

now we know if a rock is thrown it moves in a shape of a parabola which we see this equation is quadratic. Now we will use the turning point equation for a quadratic equation to get a equation for the height which the format is $f(x)= a(x-p)^2 +q$ , where (p,q) is the turning point. now we substitute the turning point