If h(x) = 5 x and k(x)=1/x, which expression is equivalent to (koh)(x)?
2 answers:
May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x 1) If h(x) = 5x and k(x) = 1/x Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x) 2) If h(x) = 5 + x and k (x) = 1/x Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
Answer:
The answer is B!! 1/(5+x)
Step-by-step explanation:
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Answer:
24
Step-by-step explanation:
Equilateral has 3 angles that add up to 180, and all angles are equal
3(2x+12) = 180
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180-36 = 6x
144 = 6x
24 = x
Answer:
The height is 7 m.
Step-by-step explanation:
Volume = 1/3 * area of the base * height, so
28 = 1/3 * 3 * 4 * h
4h = 28
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Answer:
Step-by-step explanation:
A
Volume of the cone = 1/3π r^2 h So, we are given that r = 9 and h = 12 plugging in all the known values 1/3 * (3.14) * 9 * 9 * 12 = 1017.36 cm³ or ≈1017.4 cm³
Answer:
19/24m-1/3
Step-by-step explanation:
1/6m-(-5/8m+1/3)=1/6m+5/8m-1/3=4/24m+15/24m-1/3=19/24m-1/3