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2 years ago

If h(x) = 5 x and k(x)=1/x, which expression is equivalent to (koh)(x)?

2 answers:

4 0

May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x

1) If h(x) = 5x and k(x) = 1/x

Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)

2) If h(x) = 5 + x and k (x) = 1/x

Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]

stealth61 [152]2 years ago

4 0

Answer:

The answer is B!! 1/(5+x)

Step-by-step explanation:

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What is (-11) + (-5)

yawa3891 [41]

-16 is the answer :)

6 0

3 years ago

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Suppose n(x)= 22 and n(y) is 13 what is the maximum number of elements X ∪Y can have ?

Nikolay [14]

The inclusion/exclusion principle states that

$|X\cup Y|=|X|+|Y|-|X\cap Y|$

That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).

Therefore, $|X\cup Y|$ will have the most elements when the sets $X$ and $Y$ are disjoint, i.e. $X\cap Y=\emptyset$ , which would mean the most we can can in this case would be

$|X\cup Y|=|X|+|Y|=22+13=35$

(Note that $n(X)=|X|$ denotes the cardinality of the set $X$ .)

3 0

3 years ago

In the diagram, the length of segment VS is 39 units.

Darina [25.2K]

Answer:

$TV=38\ units$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The figure shows a kite

The kite has two pairs of consecutive and congruent sides and the diagonals are perpendicular

That means

TS=VS

TQ=VQ

TR=RV

we have

$VS=39\ units$

$TS=6x-3$

$6x-3=39$

solve for x

$6x=39+3\\6x=42\\x=7$

Find the value of RV

$RV=2x+5$

substitute the value of x

$RV=2(7)+5=19\ units$

Remember that

$TV=TR+RV$ ---> by segment addition postulate

we have

$TR=RV=19\ units$

$TV=19+19=38\ units$

5 0

2 years ago

Write an equation of the circle with center (3,-2) and radius 6

Lubov Fominskaja [6]

Answer:

$\displaystyle (x-3)^2 + (y+2)^2 = 36$

Step-by-step explanation:

We want to write the equation of a circle with a center at (3, -2) and a radius of 6 units.

Recall that the equation of a circle is given by:

$\displaystyle (x-h)^2 + (y-k)^2 = r^2$

Where (h, k) is the center and r is the radius.

Since our center is at (3, -2), h = 3 and k = -2. r = 6. Substitute:

$\displaystyle (x-(3))^2 +(y-(-2))^2 = (6)^2$

Simplify:

$\displaystyle (x-3)^2 + (y+2)^2 = 36$

In conclusion, the equation of the circle will be:

$\displaystyle (x-3)^2 + (y+2)^2 = 36$

8 0

2 years ago

Hay guys can you plz help

snow_tiger [21]

We can notice from the figure that : Area of the home plate is equal to sum of the Area of the rectangle ( 8 in x 15 in) and Area of the triangle with height 6 in and base 15 in.

Area of the rectangle : Length x Width

⇒ Area of the rectangle = 15 x 8 = 120 in²

Area of the triangle : 1/2 x Base x Height

⇒ Area of the triangle = 1/2 x 15 x 6 = 45 in²

Area of the home plate = Area of rectangle + Area of triangle

⇒ Area of the home plate = 120 in² + 45 in² = 165 in²

Answer : D

3 0

2 years ago