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Basile [38]
3 years ago
13

16. Find the final balance in an account with $730 invested at 3% annual simple interest for 4 years. (1 point) $735.48 $87.60 $

817.60 $8,760.00 is the answer 817.60.
Please help me
Mathematics
1 answer:
podryga [215]3 years ago
7 0

Answer:

$817.60

Step-by-step explanation:

Simple interest has the formula:

Simple Interest = Principal * rate * time

here,

Principal amount is $730

The rate of interest is 3%, which is 3/100 = 0.03

The time length in years is given as 4

We find the interest amount first:

SI = P * r * t

SI = 730 * 0.03 * 4

SI = 87.6

We are asked to find FINAL BALANCE, which is PRINCIPAL + INTEREST

So,

Final Balance = 730 + 87.6 = $817.60

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babymother [125]

The result of simplifying each number (-3)¹/₃ . (-3)¹/₃ . (-3)¹/₃  using the exponent rules is -3

To solve this exercise we have to resolve algebraic operations following the exponent rules.

(-3)¹/₃ . (-3)¹/₃ . (-3)¹/₃

Using the product rule that indicates that: the exponent result will be the addition of these exponents, we have:

(-3)¹/₃⁺ ¹/₃ ⁺ ¹/₃

(-3)³/₃

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<h3>What is an exponent?</h3>

In mathematics an exponent is the number of time that a number, called (base) is multiplied by itself. It is also called, power or index.

Example: 3² = 3*3 = 9

Learn more about exponent at: brainly.com/question/847241

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1 year ago
Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I
dimulka [17.4K]

Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06

Find the probability of getting a mean temperature of 98.2 degrees F or lower.

This is the pvalue of Z when X = 98.2. So

Z = \frac{X - \mu}{s}

Z = \frac{98.2 - 98.6}{0.06}

Z = -6.67

Z = -6.67 has a pvalue of 0.

So there is a 0% probability of getting a mean temperature of 98.2 degrees F or lower.

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Step-by-step explanation:

b = 11

c = 11✓2 because the properties of 45 45 90 triangle

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Answer:

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Step-by-step explanation:

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