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AlladinOne [14]
3 years ago
15

Graphing inequalities

Mathematics
1 answer:
dem82 [27]3 years ago
8 0
There are three steps:<span>
1.)Rearrange the equation so "y" is on the left and everything else on the right.

2.)Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)
<span>
3.)Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).</span></span>
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what is the y-intercept of the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15
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The slope of the given line is the coefficient of x, 3/5. The slope of the perpendicular line will be the negative reciprocal of that: -1/(3/5) = -5/3.

The point-slope form of the equation for a line of slope m through point (h, k) can be written ...

... y = m(x -h) +k

For your point and the slope found above, this becomes

... y = (-5/3)(x -15) -5

When x=0, this is

... y = (-5/3)(-15) -5 = 20

The y-intercept is 20.

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