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3 years ago

How can you solve real-world and mathematical problems with numerical and algebraic equations and inequalities?

1 answer:

7 0

You can solve real-world and mathematical problems with numerical and algebraic equations and inequalities. Algebra can be applied to the temperature in different places that both change, height of a growing child over time, the speed of a car that changes over time (mph), and the age of people that increases over year. Algebra is used in parts of our everyday life, we just don’t realize it.

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Round 9,675,599 to the nearest 1,000.

BARSIC [14]

Answer: 9,676,000

Step-by-step explanation:

Increase the digit by 1 if the previous digit is 5 or above

7 0

2 years ago

Read 2 more answers

∠ABC = ___?___ <br> a) ∠MNP<br> b) ∠PMN <br> c) ∠ NPM<br> d) ∠NMP

xenn [34]

Answer:

angle ABC = angle MNP

(See the single curved shape at angle B? Match it to the same one on the other triangle. The same with the double and triple angles. The marks in the middle of the lines work the same way. Lines BC, BA, NM, and NP are all the same length.)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?

Rufina [12.5K]

$x$ is in quadrant I, so $0$ , which means $0$ , so $\dfrac x2$ belongs to the same quadrant.

Now,

$\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}$

Since $\sin x=\dfrac5{13}$ , it follows that

$\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}$

Since $x$ belongs to the first quadrant, you take the positive root ( $\cos x>0$ for $x$ in quadrant I). Then

$\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}$

$\tan x$ is also positive for $x$ in quadrant I, so you take the positive root again. You're left with

$\tan\dfrac x2=\dfrac15$

4 0

3 years ago

-a + 4a - 9 = 8a + 6

wel

Answer:

-3=a

Step-by-step explanation:

-a+4a-9=8a+6

3a-9=8a+6

3a-9-6=8a+6-6

3a-15=8a

3a-3a-15=8a-3a

-15=5a

-15/5=5a/5

-3=a

3 0

3 years ago

The sum of two nonnegative numbers is 20. Find the numbers if the sum of their squares is as large as possible; as small as poss

KATRIN_1 [288]

20 and 0 = largest sum of squares
10 and 10 = smallest

4 0

3 years ago