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3 years ago

How can you solve real-world and mathematical problems with numerical and algebraic equations and inequalities?

1 answer:

7 0

You can solve real-world and mathematical problems with numerical and algebraic equations and inequalities. Algebra can be applied to the temperature in different places that both change, height of a growing child over time, the speed of a car that changes over time (mph), and the age of people that increases over year. Algebra is used in parts of our everyday life, we just don’t realize it.

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Hello can I have some help with this expand question 4(z+2)+4(z+3)

wel

Step-by-step explanation:

4(z+2)+4(z+3)

=4z+8+4z+12

=8z+20

by simplifying-

=2z+5

4 0

3 years ago

Read 2 more answers

What is the concentration after 11 minutes? Ground to 3 decimal places.

sergiy2304 [10]

In order to find the concentration after 11 minutes, let's use the value of t = 11 in the function C(t) and then calculate its value:

$\begin{gathered} C(t)=0.04(1-e^{-0.2t}) \\ C(11)=0.04(1-e^{-2.2}_{}) \\ C(11)=0.04(1-0.1108) \\ C(11)=0.04\cdot0.8892 \\ C(11)=0.035568 \end{gathered}$

Rounding to three decimal places, we have a concentration of 0.036.

7 0

1 year ago

Proof sin^3xcos^4x=sinx(cos^4x-cos^6x)

Alina [70]

Sin³(x)cos⁴(x) = sin(x)[cos⁴(x) - cos⁶(x)]
sin(x) sin(x)
sin²(x)cos⁴(x) = cos⁴(x) - cos⁶(x)
sin²(x)cos⁴(x) = cos⁴(x)[1] - cos⁴(x)[cos²(x)]
sin²(x)cos⁴(x) = cos⁴(x)[1 - cos²(x)}
cos⁴(x) cos⁴(x)
sin²(x) = 1 - cos²(x)
+ cos²(x) + cos²(x)
1 = 1

8 0

3 years ago

Please show work

Anit [1.1K]

(1)

since both equations express y in terms of x, equate the right sides

- 2x = - 4x + 10 ( subtract 4x from both sides )

2x = 10 ( divide both sides by 2 )

x = 5

substitute x = 5 into y = - 2x → y = - 10

solution is : (x, y ) → (5, - 10 )

(2)

equate the right sides of both equations

3x = 2x - 7 ( subtract 2x from both sides )

x = - 7

substitute x = - 7 into y = 3x → y = - 21

solution is : (x, y) → (- 7, - 21)

(3)

substitute y = - 8 into the other equation

- 8 = 6x + 22 ( subtract 22 from both sides )

- 30 = 6x ( divide both sides by 6 )

x = - 5

solution is : (x, y ) → (- 5, - 8 )

6 0

3 years ago

13. Oscar's dog house is shaped like a tent. The slanted sides are both 5 feet

VashaNatasha [74]

Answer:

The height of the dog house = 4 feet.

Step-by-step explanation:

Given:

The shape of the dog house is like a tent.

The slant heights of the house is 5 feet.

The bottom of the house is 6 feet across.

To find the height of the dog house at its tallest point.

Solution:

On drawing the figure of the dog house in the shape of a tent, we find out that the tallest point would be at the midpoint of the bottom of the house.

Thus, we ave a right triangle, of which one leg = $\frac{6\ ft}{2}=3\ ft$ and hypotenuse = $5\ ft$