Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
Answer:
y=20
x=4
Step-by-step explanation:
Since you can plug the first 2 coordinates into the slope equation (
) you will get 4 for the slope so for the equation for the parallel line you would get y=4x+4 and since the x=4 you could plug that in and you would get y=20 and x=4
Answer:
a) 0
b)2
Step-by-step explanation:
a) Basically, the question is asking what the x value is when the y value is at 4, which would be 0.
b) Same thing here, but with the x value is when the y value is -2.
