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nevsk [136]
4 years ago
13

The sum of two consecutive interferes is at least 7 (n and n + 1 represent two interferes

Mathematics
1 answer:
vesna_86 [32]4 years ago
6 0
Consecutive integers are 1 apart so they are n and n+1

their sum (add) is at least 7
sum<u>></u>7

sum means add
n+n+1<u>></u>7
2n+1<u>></u>7
minus 7 both sides
2n<u>></u>6
divide 2
n<u>></u>3

the smaller number mist be at least 3, (making the bigger number at least 4)
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The quotient is x - 29, and the remainder is 234.

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[x - 3][x - 20] >> Factored Form

Obviously, this is not a zero. Now, to get the remainder, we have to plug in the vertical line of <em>x = -6</em> into its conjugate, meaning an expression with opposite signs, which is <em>x + 6</em>. This is the expression we divide the dividend by, so you will have this:

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Since the divisor is in the form of <em>x - c</em>, using Synthetic Division, we get this:

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You see? You have <em>x - 29</em> in the quotient, and you have 234 as the numerator remainder.

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