Answer:
-y² - 4y - 6
Step-by-step explanation:
Step 1: Write expression
5y² - 6y - 11 - 6y² + 2y + 5
Step 2: Combine like terms (y²)
-y² - 6y - 11 + 2y + 5
Step 3: Combine like terms (y)
-y² - 4y - 11 + 5
Step 4: Combine like terms (constants)
-y² - 4y - 6
Use Law of Cooling:

T0 = initial temperature, TA = ambient or final temperature
First solve for k using given info, T(3) = 42

Substituting k back into cooling equation gives:

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:

Solve for x:

Sub back into original cooling equation, x = T(t)

Solve for t:

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
Answer:
v = -3
Step-by-step explanation:
1) Expand.
3v + 4v - 8 = -29
2) Simplify 3v + 4v - 8 to 7v - 8.
7v - 8 = -29
3) Add 8 to both sides.
7v = -29 + 8
4) Simplify -29 + 8 to -21.
7v = -21
5) Divide both sides by 7.
v = -21/7
6) Simplify 21/7 to 3.
v = -3
Answer:
20 tea bags
Step-by-step explanation:
if 5 is 1 gallon then you do 5x4=20