3 years ago

Enter the polynomial in standard form. then enter the leading coefficient 4x -30x^3 -3x^2

1 answer:

4 0

Okay I'm going to give you an example and steps so you know how to do this

1+2x^2-4-x^2+x
Subtract 4 from 1 to get -3
2x^2-3-x^2+x
Subract x^2 from 2x^2 to get x^2
X^2-3+x
Move -3
x^2+x-3

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Calling x and y the two sizes of the rectangular field, the problem consists in finding the minimum values of x and y that give an area of $A=180000 m^2$ .
The area is the product between the two sizes:
$A=xy$ (1)
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From (1) we can write
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$p=2(x+ \frac{A}{x})=2x+2 \frac{A}{x}$

To find the minimum value of the perimeter, we have to calculate its derivative and put it equal to zero:
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$y= \frac{A}{x}= \frac{180000 m^2}{424.26 m} =424.26 m$

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