Answer:
No because upon subtracting x on both sides you obtain a false equation of 4=8.
The problem:
What are x values that satisfy:
x+4=x+8?
Step-by-step explanation:
No number can be substituted into x+4=x+8 to make it true.
There is no number that you can find such that when you add 4 to it will give you the same as adding 8 to it.
Also if you subtract x on both sides you obtain the equation 4=8.
4=8 is not true so x+4=x+8 is never true for any x.
Simplified expression for total amount spent is 10(2.05 + m)
Step-by-step explanation:
- Step 1: Write expression for expense on joining cooking club for m months.
Expense = 8.50 + 6.25 × m
- Step 2: Write expression for expense on joining movie club for m months.
Expense = 12 + 3.75 × m
- Step 3: Calculate the total amount spent on both clubs
Total Amount = 8.50 + 6.25m + 12 + 3.75m = 20.5 + 10m = 10(2.05 + m)
Answer:
5th degree
Step-by-step explanation:
To solve this problem/table, you have to find the differences in the f(x) side of the table until the differences between the numbers are the same, and then you have your degree. Look at the image attached for more sense
Piecewise Function is like multiple functions with a speific/given domain in one set, or three in one for easier understanding, perhaps.
To evaluate the function, we have to check which value to evalue and which domain is fit or perfect for the three functions.
Since we want to evaluate x = -8 and x = 4. That means x^2 cannot be used because the given domain is less than -8 and 4. For the cube root of x, the domain is given from -8 to 1. That meand we can substitute x = -8 in the cube root function because the cube root contains -8 in domain but can't substitute x = 4 in since it doesn't contain 4 in domain.
Last is the constant function where x ≥ 1. We can substitute x = 4 because it is contained in domain.
Therefore:
![\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 8} \\ f(4) = 3 \end{cases}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20%20%5Csqrt%5B3%5D%7B%20-%208%7D%20%20%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D)
The nth root of a can contain negative number only if n is an odd number.
![\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 2 \times - 2 \times - 2} \\ f(4) = 3 \end{cases}} \\ \large{ \begin{cases} f( - 8 ) = - 2\\ f(4) = 3 \end{cases}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20%20%5Csqrt%5B3%5D%7B%20-%202%20%5Ctimes%20-%20%202%20%5Ctimes%20%20%20-%202%7D%20%20%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D%20%5C%5C%20%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20-%202%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D)
Answer