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shtirl [24]
3 years ago
9

Customers at Beans Coffee Shop have entered their name in a drawing for one of 4 gift cards. The gift cards each have a value of

$10. If 79 customers enter the drawing, what is the total number of ways Beans Coffee Shop could choose the winners?
Mathematics
1 answer:
Dimas [21]3 years ago
8 0

Answer:

36,060,024 ways

Step-by-step explanation:

To choose the winner in this case, the order is very important because it determines who is chosen first  out of the seventy-nine customers whose names were entered for the draw.

The above supports the reason Permutation will be used instead of Combination.

The total number of ways is given by:

⁷⁹P₄ = 79!/(79-4)!

       =  79!/75!

       = [79 x 78 x 77 x 76 x75!]/75!

       = 79 x 78 x 77 x 76

       =   36,060,024 ways

This implies that there are  36,060,024 ways the Bean Coffee Shop could choose the winners.

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FrozenT [24]

Answer:

-3/5

Step-by-step explanation:

10-8/4-12=-0.6=-3/5

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Nadusha1986 [10]

Answer:

The height of the cylinder is 4x units.

Step-by-step explanation:

volume of a cylinder = nr^2h

n = 22/7

r = radius = x/2

Let illustrate with an example. If the diameter of a cylinder is 6 and the volume is 6^3 = 216. The radius = 6/2 = 3

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Required information An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiv
Natasha2012 [34]

Answer:

652.6-2.01\frac{311.7}{\sqrt{50}}=563.997    

652.6+2.01\frac{311.7}{\sqrt{50}}=741.203    

So on this case the 95% confidence interval would be given by (563.997;741.203)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=652.6 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=311.7 represent the sample standard deviation

n=50 represent the sample size  

Soltuion to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=50-1=49

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that t_{\alpha/2}=2.01

Now we have everything in order to replace into formula (1):

652.6-2.01\frac{311.7}{\sqrt{50}}=563.997    

652.6+2.01\frac{311.7}{\sqrt{50}}=741.203    

So on this case the 95% confidence interval would be given by (563.997;741.203)    

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I don't know the answer because i don't know the question

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Answer:

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