3/12 + 10/12 = 13/12 because the points lie in-between the 1/6 and 2/6 marks and the 6/6 and 7/6 marks.
Find and graph the feasible region for the following constraints: x + y < 5. 2x<span> + y > 4 ... y = 10/3. x = 30/3 - 10/3 = 20/3. Intersects at (20/3, 10/3). -x + </span>2y<span> = 0. x - </span>2y = 0.
When you solve, a quadratic formula is set up as ax^2+bx+c so in this scenario a is 1, b is -1 and c is -6.
-(-1)+- √- 1^2-4(1)(-1)/2(1) is
1+/-√1+4/2 equals -2 and 3 making the answer c
The slope of this line is 1/3
