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3 years ago

Help please whice h i foreach is rih

Mathematics

1 answer:

AveGali [126]3 years ago

6 0

Triangle ABC is a "right" triangle and "scalene" (because no side is equal).

BC^2 = 1^2 + 2^2
(from B(-1,1) and C(0,-1) ; x=|xc-xb|= |0-(-1)| = 1 , y=|yc-yb|= |-1-1| =2)

BC^2 = 1+4
so the measure of BC = √5 ≈ 2.2

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<img src="https://tex.z-dn.net/?f=%5Csqrt%2096" id="TexFormula1" title="\sqrt 96" alt="\sqrt 96" align="absmiddle" class="latex-

klasskru [66]

Answer:

If it is $\sqrt{96} \sqrt{96}$ then it is the solution $\sqrt{96} \sqrt{96} = 96$ because the square root of an expression multiplied by itself gives that expression.

7 0

3 years ago

If cosA=4/5 and cosB=3/5 then find a,b,c

aliya0001 [1]

Answer:

a = 3, b = 4, c = 5

Step-by-step explanation:

Assuming we're working with a right triangle, where c is the hypotenuse, then using the definition of the cosine being the adjacent side over the hypotenuse, then we know:

a = 3, because it is the side adjacent to B

b = 4, because it is the side adjacent to A

c = 5, because it is the denominator in bot fractions

This of course assumes that there is no additional ratio in place. For example, if the lengths were instead 8, 6 and 10 respectively, then the cosines given would still be 4/5 and 3/5. Truthfully these only tell relative sizes of the sides, and not their absolute sizes.

3 0

3 years ago

Read 2 more answers

Assume that the distance from Earth to the moon is exactly 238,855 miles and that it took astronauts 75 hours to reach the moon

Neko [114]

You would do 238855 divided by 75 ===3184.73333 mph

5 0

3 years ago

Read 2 more answers

4) The path of a satellite orbiting the earth causes it to pass directly over two

Naily [24]

Answers:

Satellite is approximately <u>2446.43 km</u> from station A.
Satellite is approximately <u>2441.61 km</u> above the ground.

=========================================================

Explanation:

I'm assuming tracking stations A and B are at the same elevation and are on flat ground. In reality, this is likely not the case; however, for the sake of simplicity, we'll assume this is the case.

The diagram is shown below. Points A and B describe the two stations, while point C is the satellite's location. Point D is on the ground directly below the satellite. We have these lengths

AB = 60 km
AD = x
CD = h

Focusing on triangle ACD, we can apply the tangent rule to isolate h.

tan(angle) = opposite/adjacent

tan(A) = CD/AD

tan(86.4) = h/x

x*tan(86.4) = h

h = x*tan(86.4)

We'll use this later in the substitution below.

--------------------

Now move onto triangle BCD. For the reference angle B = 85, we can use the tangent rule to say

tan(angle) = opposite/adjacent

tan(B) = CD/DB

tan(B) = CD/(DA+AB)

tan(85) = h/(x+60)

tan(85)*(x+60) = h

tan(85)*(x+60) = x*tan(86.4) ............. apply substitution; isolate x

x*tan(85)+60*tan(85) = x*tan(86.4)

60*tan(85) = x*tan(86.4)-x*tan(85)

60*tan(85) = x*(tan(86.4)-tan(85))

x*(tan(86.4)-tan(85)) = 60*tan(85)

x = 60*tan(85)/(tan(86.4)-tan(85))

x = 153.612786190499

--------------------

We'll use this approximate x value to find h

h = x*tan(86.4)

h = 153.612786190499*tan(86.4)

h = 2441.60531869599

h = 2441.61 km is how high the satellite is above the ground.

Return to triangle ACD. We'll use the cosine rule to determine the length of the hypotenuse AC

cos(angle) = adjacent/hypotenuse

cos(A) = AD/AC

cos(86.4) = x/AC

cos(86.4) = 153.612786190499/AC

AC*cos(86.4) = 153.612786190499

AC = 153.612786190499/cos(86.4)

AC = 2446.43279498247

AC = 2446.43 km is the distance from the satellite to station A.

6 0

3 years ago

What aspect of the town are most at risk for damage by the fire??

Stolb23 [73]

Answer:

Trees.

Step-by-step explanation:

The houses look sturdy, and not that flammable. The trees and grass are very plentiful, so they would spread easily.

Please clarify if this wasn't what you were asking.

7 0

3 years ago