Answer:
There is no point of the form (-1, y) on the curve where the tangent is horizontal
Step-by-step explanation:
Notice that when x = - 1. then dy/dx becomes:
dy/dx= (y+2) / (2y+1)
therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:
0 = ( y + 2) / (2 y + 1)
And we obtain y = -2 as the answer.
But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:
(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2 (instead of zero)
Then, we conclude that there is no horizontal tangent to the curve for x = -1.
Answer:
Try 458.96 (round if needed)
Step-by-step explanation:
First you find the volume of the cone. (pi*radius^2*h/3)
Then you find the volume of a cylinder. (pi*radius^2*h) add these two up.
You would have to subtract 12.5 and 8.5 to get the height of the cone.
Also you would have to subtract 6 inches off of your total.
(Sorry If this explanation sucked.)
Answer:
like write an equation? If so it's a 0 slope
Step-by-step explanation:
