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RUDIKE [14]
3 years ago
6

In hopes of encouraging healthier snacks at school, Brian brought in a tray of carrot sticks and apple slices to share. ​ ​The t

ray had a total of 60 snacks, of which 20% were carrot sticks. ​ ​How many carrot sticks did Brian bring? Answer:​
Mathematics
2 answers:
Xelga [282]3 years ago
6 0

Answer:

34%

Step-by-step explanation:

elixir [45]3 years ago
3 0

Answer:40 %  of the snacks were carrot sticks.

Step-by-step explanation:

Total number of carrot sticks in lunch = 18

Total number of apple slices in lunch = 27

So, Total Snacks in the Lunch = Carrot Sticks + Apple Slices

                                                  = 18 +  27 = 45

Step-by-step explanation:

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a) 14

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Step-by-step explanation:

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What is the measure of OAC
Lady bird [3.3K]

Answer:

27°

Step-by-step explanation:

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If ∧ ASC ≅ ∧ KSC then ∠8 is congruent to which angle?
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Answer:

B. angle 5

Step-by-step explanation:

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3 years ago
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7 0
2 years ago
A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D.
yKpoI14uk [10]

The correct statement is:

  • There are four ways to choose the committee.
  • There are three ways to form the committee if person D must be on it.
  • If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1) There are four ways to choose the committee.

This statement is true.

Since we have to choose 3 members out of the 4 members so we can use the method of combination.

2) There are three ways to form the committee if person D must be on it.

This statement is also true.

Since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3) If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

There are 35 combinations possible.

4) If persons B and C must be on the committee, there are two ways to form the committee.

If B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5) If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be on the committee then as in the last option we have to choose any one of the two-person left.

So possible number of ways is 2.

Hence, the statement is false.

Learn more about committee here: brainly.com/question/425830

#SPJ4

<em>Your question is incomplete. Please read below to find the missing content.</em>

<em />

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D. The possible outcomes include S = {ABC, ABD, ACD, BCD}.

Which statements about the situation are true? Check all that apply.

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If seven members are eligible next year, then there will be fewer combinations.

If persons B and C must be on the committee, there are two ways to form the committee.

If persons A and C must be on the committee, then there is only one way to form the committee.

8 0
2 years ago
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