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kolbaska11 [484]
3 years ago
6

What is the radius of a sphere with the volume of 972pi mm

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0

\large\text{Hey there!}

\mathsf{The\ sphere\ formula\ is: \dfrac{4}{3}\pi\times r^3}

\mathsf{Now, that\ we\ have\ our\ formula\ let's\ solve\ for\ the\ equation}

\mathsf{So,\ first\ \bf{\underline{DIVIDE}}}\mathsf{\ both\ of\ your\ sides\ by\  \pi}

\mathsf{\dfrac{4}{3}r^3=972}\\\\\rightarrow\ \mathsf{r^3=972\times\dfrac{3}{4}}\\\\\mathsf{972\times\dfrac{3}{4}=729}\\\\\mathsf{\rightarrow\ r^3=729}

\mathsf{\sqrt[\mathsf{3}]{\mathsf{729}} = 81}\\\\\mathsf{\sqrt{81}=81\div9=9}\\\\\mathsf{\sqrt{81}=9}\\\\\mathsf{r=9}

\boxed{\boxed{\mathsf{\bf{Answer: \boxed{\mathsf{radius = \bf{9}}}}}}}\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\dfrac{\frak{LoveYourselfFirst}}{:)}

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2. The IQR for Data Set A is larger than the IQR for Data Set B.

4. The IQR for Data Set A and Data Set B measures the middle 50% of the data.

Step-by-step explanation:

IQR is an abbreviated form of the word Interquartile range. It is used as a measure in statistics for a set of given data.

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Interquartile range can also be referred to or known as the Median(middle) of a given set of data.

Interquartile range is determined by arrange the given set of data from the lowest to height number and then we find or pick the number that is in the middle as our Interquartile range. If the number of term of a given set of data is even in number, we pick two numbers in the middle, add them together and divide it by 2.

In the question above, the correct statements that Francis can make about a given set of data is :

2. "The IQR for Data Set A is larger than the IQR for Data Set B" and

4. The IQR for Data Set A and Data Set B measures the middle 50% of the data.

This is because

Data Set A: 20, 25, 28, 30, 39, 40

Since the number of terms in data set A is 6 (i.e an even number) hence, we pick the two numbers in the middle

The Interquartile range for Data Set A= (28+30) ÷ 2 = 58÷ 2 = 29

For Data Set B: 20, 22, 23, 27, 30, 42

The number of terms in data set is 6( i.e an even number), likewise we pick the two numbers in the middle

The Interquartile range for Data Set B

= (23+27) ÷ 2 = 50÷ 2 = 25

From the above calculation, we have proved that option 2 is correct. The Interquartile range of Data Set A which is 29 is larger than the Interquartile range of Data Set B which is 25.

Likewise Option 4 is correct as well , because the Interquartile range of both Data set A and Data set B measured the middle 50% of the data.

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