i used polynomial division.. i hope this helps :)
Answer:
4
Step-by-step explanation:
Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
1st data set:
Minimum: 34
1st quartile: 35
Median: 36
3rd quartile: 37
Maximum: 38
Second data set:
Minimum: 20
1st quartile: 23
Median: 25
3rd quartile: 38
Maximum: 65
Graph
it based on the values of the 1st and 3rd quartile. If they are both
the same number away from the mean then they are symmetrical. Otherwise
they are not. In this case, the first one is similar and the second one
is not.
Please mark as brainiest!
Cheers
