· In an open system matter and energy can be transferred
· In a closed system only energy can be exchanged
· In an isolated system neither matter nor energy can be exchanged
· The cell has to be an open system because it needs to exchange matter and energy and the only way to do so is through an open system
· As an open system the cell allows nutrients to enter the cell and waste products to exit the cell
· The cell does this through the use of a semi-permeable membrane
· It needs nutrients in the forms of glucose, ions and many other molecules.
· The nutrients can come into the cell through either passive or active transport
· In passive transport the nutrients naturally move from a higher concentration gradient to a concentration gradient.
· During active transport the particle need to move against the concentration gradient. To do this the cell needs energy to transport the materials. The energy comes in the form of ATP.
The cell will undergo osmotic lysis. 3. The cell will plasmolyze.
Answer:
Myelin sheaths refer to the covering of fatty tissue, which safeguards the nerve cells. These cells are the components of CNS that conduct messages back and forth between the brain and the remaining parts of the body.
The majority of the nerve fibers are enveloped by an insulating, fatty sheath known as myelin that functions to accelerate the impulses. The myelin sheath comprises periodic breaks known as nodes of Ranvier. Hopping from nodes to nodes, the impulse can pass much more briskly than if it had to move along the whole length of the nerve fiber.
Practice will help a person be a good athlete. Although body structure is genetic and can influence the athletic ability, practice pays an more important role.
The question is incomplete and the complete question is
Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.
Answer:
AABb or AaBB
Explanation:
We know that,
aabb genotype - 6 cm
AABB genotype- 16-cm
To calculate the length of earlobe contributed by each allele in a genotype is :
1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)
2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)
Now to have the earlobe to be 13.5 cm long then the genotype must be
13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B
Therefore, the genotype will be-either AABb or AaBB