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wel
3 years ago
9

Help me I’m in a rush!!

Mathematics
1 answer:
Komok [63]3 years ago
4 0

21. Find the unit rate ($ per fl oz). Compare the two prices.

22. Multiply 2 3/5 by 7, and 5 3/4 by 4. Add those together and get the answer.


Hope that helps!

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If X = 7 units, Y = 4 units, Z = 18 units, and h = 7 units, what is the surface area of the triangular prism shown above?
nata0808 [166]

Answer:

Step-by-step explanation:

3 0
3 years ago
What is the average rate of change from x = -1 x = 2 equal to 5?
kherson [118]
Yes. And thanks.for free branana
7 0
3 years ago
Find an equation of the tangent plane to the surface z=ln(x-6y) at the point(7,1,0)
expeople1 [14]

The tangent plane equation of tangent plane is

z = x - 6y -1

This is further explained below.

What is the equation of the tangent plane to the surface z=ln(x-6y) at the point(7,1,0)?

Generally, Given surface is z = ln(x − 6y) ,

Given point is (x_0, y_0 , z_0) = (7, 1, 0)

partially differentiating with respect to x

== >zx = [1/(x - 6y)] (1) = 1/(x - 6y)

zx (7 , 1 , 0) = 1/(7 - 6(1)) = 1

Partially differentiating with respect to y

zy = [1/(x - 6y)] (-6)

zy = -6/(x - 6y)

zy(7 , 1 , 0) = -6/(7 - 6(1)) = -6

Equation of tangent plane is z - z_0 = zx(x -x_0) + zy(y - y_0)

z - 0 = 1(x - 7) + (-6)(y - 1)

z = x - 7 -6y + 6

z = x - 6y -1

In conclusion, equation of tangent plane is z = x - 6y -1

Read more about the tangent plane

brainly.com/question/10542585

#SPJ4

8 0
2 years ago
Use natural logarithms to evaluate log7 2506
elixir [45]
Using the change in base property, we have \frac{ln2506}{ln7}=4.022 approximately.
6 0
4 years ago
Pulse rates of women are normally distributed with a mean of 77.5 beats per minute and a standard deviation of 11.6 beats per mi
irakobra [83]

Answer:

a) Mean=0 and Standard deviation=1

b) The z-scores have no units of measurement

Step-by-step explanation:

When we convert all the pulse rates of women to z-scores using the formula;

z=\frac{x-\mu}{\sigma} the mean is 0 and the standard deviation is 1.

The reason is that, the resulting distribution of z-scores forms a normal distribution which has a mean of 0 and a standard deviation of 1.

b) The z-scores are standardize scores and has no units of measurement. They give us how many standard deviations below or above the mean of the corresponding values.

8 0
4 years ago
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