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Akimi4 [234]
3 years ago
6

The least common multiple of two numbers is 60, and one of the numbers is seven less than the other numbers. What are the number

s?
Mathematics
1 answer:
anastassius [24]3 years ago
7 0
Start by writing all of the pairs of numbers that go into 60

1 60
2 30
3 20
4 15
5 12
6 10


Then, look for the pair that has a difference of seven between the two numbers.

Your numbers are 5 and 12
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If a system has at least one solution, it is said to be consistent. If a consistent system has exactly one solution, it is independent.

Step-by-step explanation:

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Thank you so much!! If u get this right I'll mark you!
Semenov [28]

Hi! I hope you are having a great day! So looking here at this question I do so humbly believe that your answer is Number to and or B. all numbers Less than 7. <em>(seven) ==> ♥</em>

Explanation for Q.A.:

  1. The sign is to the right (<)
  2. If x = < 7 then it is evidently going to be B. (LOL)
  3. You are, Awesome! and I am to so yea... It is going to be right! trust me.

I hope that this is helpful to you! I also pray that you get a 100% Good luck.`♥

4 0
3 years ago
PLEASE HELP
NeTakaya

Answer:

A rectangular prism in which BA = 20 and h = 6 has a volume of 120 units3; therefore, Shannon is correct

Step-by-step explanation:

step 1

Find the area of the base of the rectangular pyramid

we know that

The volume of the rectangular pyramid is equal to

V=\frac{1}{3}BH

where

B is the area of the base

H is the height of the pyramid

we have

V=40\ units^{3}

H=6\ units

substitute and solve for B

40=\frac{1}{3}B(6)

120=B(6)

B=120/6=20\ units^{2}

step 2

Find the volume of the rectangular prism with the same base area and height

we know that

The volume of the rectangular prism is equal to

V=BH

we have

B=20\ units^{2}

H=6\ units

substitute

V=(20)(6)=120\ units^{3}

therefore

The rectangular prism has a volume that is three times the size of the given rectangular pyramid. Shannon is correct

3 0
3 years ago
What is a to the -6th power using a positive exponent
pentagon [3]
a^{-6}=\left(\dfrac{1}{a}\right)^6=\dfrac{1}{a^6}
5 0
3 years ago
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