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3 years ago

Solve and explain please

Mathematics

2 answers:

lilavasa [31]3 years ago

7 0

Answer:

j₁ = - 2

j₂ = - 9

Step-by-step explanation:

j² + 11j + 18 = 0

j² + 9j + 2j + 18 = 0

j(j+ 9) + 2(j + 9) = 0

(j + 2)(j + 9) = 0

j + 2 = 0 => j₁ = - 2

j + 9 = 0 => j₂ = - 9

Ann [662]3 years ago

3 0

Answer:

j= -9, -2

Step-by-step explanation:

(j+9)(j+2)

j=-9, -2

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Select the quadratic that has the roots x=8 and x=-5

mart [117]

The quadratic that has the roots x=8 and x=-5 is
x^2-3x-40

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4 years ago

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A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

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3 years ago

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baherus [9]

Answer:

Step-by-step explanation:

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3 years ago

Write the missing decimal so that each pair adds to 1. 2/5+decimal =1

I am Lyosha [343]

Answer:

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Step-by-step explanation:

We can get the answer by subtracting the decimal by one.

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2 years ago

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Lelu [443]

Answer:

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Step-by-step explanation:

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