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3 years ago

How many liters will you need to equal 20 gallons of lemonade? Round your answer to the nearest tenth of a liter.

Mathematics

2 answers:

kati45 [8]3 years ago

8 0

It is 80 :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :)

a_sh-v [17]3 years ago

5 0

75.7 liters to be exact because the full amt. not rounded is 75.7082. I got this by using conversion tables <span />

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Need help use screenshot(SAT Prep) In △ABC, AB = BC = 20 and DE ≈ 9.28. Approximate BD. bd equals?

Lilit [14]

Answer:

5.36

Step-by-step explanation:

Given that:

<BAD = <CAE, therefore, BD = EC

Let's take x to be the length of BD = EC

BD + DE + EC = BC

BC = 20,

BD = EC = x

DE ≈ 9.28

Thus,

x + 9.28 + x = 20

x + x + 9.28 = 20

2x + 9.28 = 20

Subtract 9.28 from both sides

2x + 9.28 - 9.28 = 20 - 9.28

2x = 10.72

Divided both sides by 2 to solve for x

$\frac{2x}{2} = \frac{10.72}{2}$

$x = \frac{10.72}{2}$

$x = 5.36$

BD ≈ 5.36

4 0

4 years ago

The parallelogram shown below has an area of 72 units?.<br> h<br> 13<br> Find the missing height.

Vaselesa [24]

Answer:

area is given base is given so area of parallelogram =b x h

or 72=13 x h

or h =72/13=5.5 units

6 0

3 years ago

What is the amplitude of the sinusoidal function?

dem82 [27]

Answer:

The amplitude of the sinusoidal function is 3

Step-by-step explanation:

$Amplitude=\frac{Maximum+Minimum}{2}\\\\Amplitude=\frac{1+(-7)}{2}\\ \\Amplitude=\frac{1-7}{2}\\\\Amplitude=\frac{-6}{2}\\ \\Amplitude=-3=3$

7 0

2 years ago

The price of a theater ticket increased from $7.50 to $7.75. the theater sold 315 tickets at the higher price. with the price in

Karolina [17]

7.50 X 315 =2362.50 at the lower price
7.75 X 315 = 2441.25 at the higher price

subtract 2362.50 from 2441.25 you get 78.75

3 0

3 years ago

Find the cube roots of 8(cos 216° + i sin 216°).

Tomtit [17]

$z^3=8(\cos216^\circ+i\sin216^\circ)$
$z^3=2^3(\cos(6^3)^\circ+i\sin(6^3)^\circ)$
$\implies z=8^{1/3}\left(\cos\left(\dfrac{216+360k}3\right)^\circ+i\sin\left(\dfrac{216+360k}3\right)^\circ\right)$

where $k=0,1,2$ . So the third roots are

$z=\begin{cases}2(\cos72^\circ+i\sin72^\circ)\\2(\cos192^\circ+i\sin192^\circ)\\2(\cos312^\circ+i\sin312^\circ)\end{cases}$

5 0

3 years ago