Triangles CPA and CPB are both right triangles. They share a leg, so that leg in one triangle is congruent to that leg in the other triangle. We are given that PA is congruent to PB by the hash marks on the diagram. Thus two legs and an included angle are congruent between the triangles.

... ∆CPA ≅ ∆CPB by the SAS postulate

Then side CA ≅ CB = 15 in, because corresponding parts of congruent triangles are congruent (CPCTC).

... CA is 15 in.

8 0

2 years ago

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What do two equivalent expressions always h av in common

mixer [17]

-they can get the same answer

8 0

2 years ago

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MN is the midsegment of the trapezoid ABCD. What is the length of segment AB?

vladimir1956 [14]

Dear Student,

Answer to your query is provided below:

The length of segment AB = 8

Explanation to answer is provided by attaching image.

8 0

2 years ago

NO LINKS!!!! Find the equation of the circle below

inysia [295]

Answer:

$(x+3)^2+(y-2)^2=9$

Step-by-step explanation:

Equation of a circle

$(x-a)^2+(y-b)^2=r^2$

where:

(a, b) is the center
r is the radius

From inspection of the diagram, the center of the circle appears to be at point (-3, 2), although this is not very clear. Therefore, a = -3 and b = 2.

Substitute these values into the general form of the equation of a circle:

$\implies (x-(-3))^2+(y-2)^2=r^2$

$\implies (x+3)^2+(y-2)^2=r^2$

Again, from inspection of the diagram, the maximum vertical point of the circle appears to be at y = 5. Therefore, to calculate the radius, subtract the y-value of the center point from the y-value of the maximum vertical point:

⇒ radius (r) = 5 - 2 = 3

Substitute the found value of r into the equation:

$\implies (x+3)^2+(y-2)^2=3^2$

Therefore, the final equation of the given circle is:

$\implies (x+3)^2+(y-2)^2=9$

7 0

1 year ago

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