All categories

2 years ago

Randomization in an experiment is important because it ensures that

Mathematics

1 answer:

Alexeev081 [22]2 years ago

5 0

Answer:

C.) each treatment is thought of as a value of the explanatory variable

Step-by-step explanation:

The main purpose for using randomization in an experiment is to control the lurking variable and establish a cause and effect relationship.

If we do not control lurking, or confounding, variables, we cannot accurately establish a cause and effect relationship; this means we cannot ensure that each treatment is a value of the explanatory variable.

You might be interested in

Real World Scenario:

iragen [17]

The distance of a train from the city depends on the speed, the time of

travel, and direction of motion of the train.

Correct responses:

Distance Train A is from the city: 750 - 75·t

Distance Train B is from the city: 50·t

After six hours, the two trains are the same distance from the city

At that time both trains will be 300 miles away

1) From the time of departure of Train B to just before 6 hours after Train B's departure; 0 ≤ t < 6 hours

2) At time period, t > 6 hours

3) 250 miles

<h3>Method used to find the above response</h3>

Given:

The distance of train A from the city = 750 miles

Speed of train A = 75 mph

Time at which Train B leaves the city = When Train A is 750 miles from the city

Speed of Train B = 50 mph

Solution:

The equations are;

Distance of Train A from the city is; x₁ = 750 - 75·t

Distance of Train B from the city is x₂ = 50·t

When the train are the same distance from the city, we have;

750 - 75·t = 50·t

750 = 50·t + 75·t = 125·t

Therefore;

$t = \mathbf{\dfrac{750}{125}} = 6$

The time it takes the two trains to be the same distance from the city is 6 hours.

Which gives;

After 6 hours, the two trains are the same distance from the city.

The distance the trains will be after 6 hours is therefore;

750 - 75 × 6 = 300

The distance of the trains from the city after 6 hours = 300 miles

Therefore, we have;

At that time both trains will be 300 miles away

1) The time period Train A is further from the city is before the first 6 hours elapse; 0 hours ≤ t < 6 hours

2) The Train B is further from the city after 6 hours of its departure from the city; t > 6 hours

3) The distance of Train A from the city after 4 hours is given as follows;

x₁ = 750 - 75 × 4 = 450

x₁ = 450 miles

The distance of Train B from the city after 4 hours is; x₂ = 50 × 4 = 200

x₂ = 200 miles

Therefore;

The distance between the trains after 4 hours = 450 miles - 200 miles = 250 miles

Learn more about distance and time relationship equation here:

brainly.com/question/10804931

3 0

1 year ago

Which statements about the cylinder are true? Select two

Rus_ich [418]

Answer:

The radius of the cylinder is (1/2)x units

The area of the cylinder’s base is (1/4)πx2 square units

The height of the cylinder is 4x units

Step-by-step explanation:

The complete question is

A cylinder with a base diameter of x units has a volume of πx3 cubic units.

Which statements about the cylinder are true? Check all that apply.

(1) The radius of the cylinder is (1/2)x units.

(2) The radius of the cylinder is 2x units.

(3) The area of the cylinder’s base is (1/4)πx2 square units.

(4) The area of the cylinder’s base is (1/2)πx2 square units.

(5) The height of the cylinder is 2x units.

(6) The height of the cylinder is 4x units

we know that

The volume of the cylinder is equal to

$V=\pi r^{2}h$

we have

$r=\frac{x}{2}\ units$ ----> the radius is half the diameter

$V=\pi x^{3}\ units^3$

substitute the given values in the formula of volume

$\pi x^3=\pi (\frac{x}{2})^{2}h$

solve for h

simplify

$x=(\frac{1}{4})h$

$h=4x\ units$

Verify each statement

(1) The radius of the cylinder is (1/2)x units

The statement is true

see the explanation

(2) The radius of the cylinder is 2x units.

The statement is false

Because, the radius of the cylinder is x/2 units

(3) The area of the cylinder’s base is (1/4)πx2 square units

The statement is true

Because, the area of the cylinder's base is equal to

$A=\pi r^{2}$

$r=\frac{x}{2}\ units$

substitute

$A=\pi (\frac{x}{2})^{2}$

$A=\frac{\pi x^2}{4}\ units^2$

(4) The area of the cylinder’s base is (1/2)πx2 square units.

The statement is false

Because, the area of the cylinder's base is equal to

$A=\frac{\pi x^2}{4}\ units^2$

see the part (3)

(5) The height of the cylinder is 2x units.

The statement is false

Because, the height of the cylinder is 4x units (see the explanation)

(6) The height of the cylinder is 4x units

The statement is true

see the explanation

7 0

2 years ago

PLZ HELP ME ON THISSS!!

gavmur [86]

Answer:

1.12

2.10

3.11.40

4.10.48

5.10.95

6.10.72

7.11.53

Step-by-step explanation:

you can put them in order

6 0

2 years ago

Read 2 more answers

Determine whether the degree of the function is even or odd and whether the function itself is even or odd.

Fynjy0 [20]

Answer:

There are Even, Odd and None of them and this does not depend on the degree but on the relation. An Even function: $f(-x)=f(x)$ And Odd one: $-f(x)=f(-x)$

Step-by-step explanation:

1) Firstly let's remember the definition of Even and Odd function.

An Even function satisfies this relation:

$f(-x)=f(x)$

An Odd function satisfies that:

$-f(x)=f(-x)$

2) Since no function has been given. let's choose some nonlinear functions and test with respect to their degree:

$f(x)=x^{2}-4, g(x)= x^{5}+x^{3}$

$f(x)=x^2 -4\Rightarrow f(-x)=(-x)^{2}-4\Rightarrow f(-x)=x^{2}-4\therefore f(x)=f(-x)$

$g(-x)=-(x^{5}+x^{3})\Rightarrow g(-x)=-x^{5}-x^{3}\Rightarrow g(-x)=-g(x)$

3) Then these functions are respectively even and odd, because they passed on the test for even and odd functions namely, $f(-x)=f(x)$ and $-f(x)=f(x)$ for odd functions.

Since we need to have symmetry to y axis to Even functions, and Symmetry to Odd functions, and moreover, there are cases of not even or odd functions we must test each one case by case.

7 0

3 years ago

Apples in a french market cost 2.5 Euros per kilogram. what is the price in dollars per pound. (Based on $ 1.256 - Euros .7965)

Alika [10]

2.5euros/1kg×?U.S$/?euro×1kg/?lb
and, 1 kg=2.20462 lb
2.5/1 * $1.256/.7965 E * 1KG/2.204 =3.14/178= 1.76.

4 0

3 years ago