Answer:
the approximate probability that the total weight of the passengers exceeds 4668 pounds is 0.0089
Step-by-step explanation:
Using the central limit Theorem
z = (x - u )/Q÷ sqrt n
Where z is the z-score
x is the average weight = 4668/22 = 212.2
u is the passengers average = 194 pounds
Q is standard deviation = 36 pounds
Therefore
z= (212.2 - 194) / 36 ÷ sqrt22
= 18.2/ 36÷ 4.69
= 18.2/7.68
z=2.3698 aprx 2.37
Find the value of 2.37 z-score on the z-table to determine the approximate probability
P(z>2.37) = 0.0089 (from the z-table)
Answer: Bradley would expect 94 times to get a blue or green gumball.
Step-by-step explanation:
Since we have given that
Number of blue gumballs = 15
Number of yellow gumballs = 12
Number of green gumballs = 2
Number of purple gumballs = 16
Total number of all gumballs = 45
Probability of getting either a blue gumball or green gumball be
So, Expectation of getting a blue gumball or green gumball if a gumball was taken out 250 times :
Since we know that it must be less than 94.4.
So, the nearest smallest integer will be 94 times .
Hence, Bradley would expect 94 times to get a blue or green gumball.
Answer:
y² + 2 x y
Step-by-step explanation:
Given polynomials
x² + 3x y -y² and x² + 5xy
The subtract x² + 3x y -y² from x² + 5xy
x² + 5xy - ( x² + 3x y -y²)
⇒ x² + 5xy -x² - 3xy +y²
⇒ 2 x y + y²
Answer: 0.25 or 25%
Step-by-step explanation: