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vaieri [72.5K]
3 years ago
15

Need help with this question for an exam!

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

The answer is x=-2 and x=4

Step-by-step explanation:

The attachment 1 is the graph of f(x), the attachment 2 is the graph of g(x)

Mergin the two functions, you will have this

Wichh shows you that the 2 graph intersect when x=2 and x=4

It is more straight to solve the equation

\frac{-x^{2} }{2} = -x-4

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If f(x) = x2 + 1, find f(a + 1).<br> a2+2<br> a2+a+1<br> a2+ 2a + 2
torisob [31]

Answer:

a^2 + 2a + 2

Step-by-step explanation:

replace x with (a +1) everywhere in the equation

f(a+1) = (a+1)^2 + 1

➡

a^2 + 2a + 1 + 1

7 0
4 years ago
Lamooooo yall didn't wanna play somebody reported and got it token down XD
lakkis [162]

Answer:

oof

Step-by-step explanation:

idek bro

7 0
3 years ago
2. Which answer of
bagirrra123 [75]

Answer: B : 12+3=15

Step-by-step explanation:

A sum is the answer of an addition problem

4 0
1 year ago
<img src="https://tex.z-dn.net/?f=%20%20log_%7B2%7D%28x%29%20%20%3D%20%20-%204" id="TexFormula1" title=" log_{2}(x) = - 4" al
JulsSmile [24]

Answer: x = 1/16

Step-by-step explanation:

Since the inverse of a Logarithm is an exponential function, we know that the final solution has to involve an exponential function somewhere in it.

1. log B(2) {x} = -4  || given

2. x = 2 ^ -4  || Logarithm rule that allows you to move the base of the logarithm to the base of the exponent on the other side. For example, if you had log B(5) {x} = 3, the base of 5 would move over to the other side and it would be raised to 3; x = 5^3.

3. x = (1) / (2^4) || Simplify. Use the negative exponent rule. This rule always leaves a numerator of 1, and a denominator of your exponent. In this case, it will be 2 ^ -4, so you will do 2^4 which is 16 and you will put that over 1. Resulting in your final answer of x = 1/16

3 0
3 years ago
Find the area of the shaded region. Round to the nearest tenth.
sukhopar [10]

Answer:

Step-by-step explanation:

r = 8.35 ft

area of circle = πr² = 69.7225π ft²

θ = 5π/9 radians

area of unshaded segment = r²(θ-sinθ)/2 ≅ 26.51 ft²

shaded region = 69.7225π - 26.51 ≅ 192.53 ft²

7 0
3 years ago
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