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Nutka1998 [239]
3 years ago
14

What is a positive and a negative number between 1 and -1 ? ​

Mathematics
1 answer:
kherson [118]3 years ago
6 0

Answer:

The answer is 0

Step-by-step explanation:

It's between -1 and 1 and it's not positive only and it's not negative only

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1.Suppose f(x)=6x^2+2x-7 and g(x)=4x-3.Find the value of f(5)/g(-3)
posledela

Answer:

<em><u>-</u></em><em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u>2</u></em>

Step-by-step explanation:

<u>f</u><u>{</u><u>5</u><u>}</u> = <u>6</u><u>(</u><u>5</u><u>^</u><u>2</u><u>)</u><u> </u><u>+</u><u> </u><u>2</u><u>(</u><u>5</u><u>)</u><u> </u><u>-</u><u> </u><u>7</u>

g{-3}= 4(-3)-3

= <u>6</u><u>(</u><u>2</u><u>5</u><u>)</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u><u> </u><u>-</u><u> </u><u>7</u>

-12 - 3

= <u>150</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u><u> </u><u>-</u><u> </u><u>7</u>

- 15

= <u>1</u><u>5</u><u>3</u>

-15

= <u>-</u><u>5</u><u>1</u>

5

= <em><u>-</u></em><em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u>2</u></em>

7 0
3 years ago
Plz help asappppppppp!!!
MAVERICK [17]

Answer:

10, 22, 48.4, 106.48, 234.256

Step-by-step explanation:

The first term is already given it is 10.

The second term is the first term times 2.2.

10×2.2=22

The second term is 22.

The third term is the second term times 2.2.

22×2.2=48.4

The third term is 48.4.

The fourth term is the third term times 2.2.

48.4×2.2=106.48

The fourth term is 106.48.

The fifth term is the fourth term times 2.2.

106.48×2.2=234.256

The fifth term is 234.256.

8 0
3 years ago
Does someone know the answer
BlackZzzverrR [31]
The answer to your question is c
6 0
3 years ago
If 90 percent of automobiles in Orange County have both headlights working, what is the probability that in a sample of eight au
Alex17521 [72]

Answer:

P(X \geq 7) = P(X=7) +P(X=8)

And we can find the individual probabilities using the probability mass function

P(X=7)=(8C7)(0.9)^7 (1-0.9)^{8-7}=0.3826  

P(X=8)=(8C8)(0.9)^8 (1-0.9)^{8-8}=0.4305  

And replacing we got:

P(X \geq 7) = P(X=7) +P(X=8)=0.3826 +0.4305=0.8131

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem

Let X the random variable of interest "number of automobiles with both headligths working", on this case we now that:  

X \sim Binom(n=8, p=0.9)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And for this case we want to find this probability:

P(X \geq 7) = P(X=7) +P(X=8)

And we can find the individual probabilities using the probability mass function

P(X=7)=(8C7)(0.9)^7 (1-0.9)^{8-7}=0.3826  

P(X=8)=(8C8)(0.9)^8 (1-0.9)^{8-8}=0.4305  

And replacing we got:

P(X \geq 7) = P(X=7) +P(X=8)=0.3826 +0.4305=0.8131

3 0
3 years ago
Read 2 more answers
Jake can mulch a garden in 30 minutes. together, jake and ross can mulch the same garden in 16 minutes. how much time t, in minu
Gelneren [198K]

"Jake can mulch a garden in 30 minutes." So, for 1 min Jake can mulch 1/30 part of a garden.

Ross can mulch the park for x minutes. So, for 1 min Jake can mulch 1/x part of a garden.

If they work together, for 1 min they will mulch (1/30 + 1/x) part of the garden.

At the same time, we know, that of they work together they can mulch the garden in 16 min, so for 1 min they will mulch 1/16 part of the garden.

Now, we can write an equation

\frac{1}{30}  + \frac{1}{x} = \frac{1}{16}  \\ \\ \frac{1}{x} = \frac{1}{16} - \frac{1}{30}  \\ \\ \frac{1}{x} =\frac{30-16}{16*30}  \\ \\ \frac{1}{x} =\frac{14}{16*30}  \\ \\x=\frac{16*30}{14}

x≈34.3 (min)

8 0
3 years ago
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