12001, 12002, 12003 so lol
Answer:
n=2
Step-by-step explanation:
Remember that
If the given coordinates of the vertices and foci have the form (0,10) and (0,14)
then
the transverse axis is the y-axis
so
the equation is of the form
(y-k)^2/a^2-(x-h)^2/b^2=1
In this problem
center (h,k) is equal to (0,4)
(0,a-k)) is equal to (0,10)
a=10-4=6
(0,c-k) is equal to (0,14)
c=14-4=10
Find out the value of b
b^2=c^2-a^2
b^2=10^2-6^2
b^2=64
therefore
the equation is equal to
<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>
Answer:
10 + (2 x 3)^2 / 4 x (1/2) ^3
First do the parentheses
2 x 3 = 6
1 / 2 = 0.5
We are left with
10 + 6^2 /4 x 0.5^3
Do exponents
6 x 6 = 36
0.5 x 0.5 x 0.5 = 0.125
10 + 36 / 4 x 0.125
Divide by 4 and multiply by 0.125
36 / 4 = 9
9 x 0.125 = 1.125
We are left with
10 + 1.125 = 11.125
The answer is 11.125
Step-by-step explanation:
