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alexgriva [62]
3 years ago
10

-24+15-6=x

Mathematics
2 answers:
jek_recluse [69]3 years ago
5 0

Answer:

idk to be honest

Step-by-step explanation:

plz help a sis out im rlly just trying to get the points to do my stupid homwork, feel free to do the same things on my quetions

suter [353]3 years ago
4 0

Answer:

x = -15

Step-by-step explanation:

-24 + 15 - 6 = x

-9 - 6 = x

-15 = x

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The following question has two parts. First, answer part A. Then, answer part B.
Pie

Answer:

When you're talking factors, you're talking about some sort of integer; that's because “factors” depends on the concept of divisibility, which are virtually exclusive to integers. When you're talking “greater than”, you're excluding complex numbers (where the concept of ordering doesn't exist) and you're probably assuming positive integers. If you are, then no; no positive integer has factors that are larger than it.

If you go beyond positive numbers, that changes. 0 is an integer, and has every integer, except itself, as factors; since its positive factors are greater than zero, there are factors of zero that are greater than zero. If you extend to include negative numbers, you always have both positive and negative factors; and since all positive integers are greater than all negative integers, all negative integers have factors that are greater than them.

Beyond zero, though, no integer has factors whose magnitudes are greater than its own. And that's a principle that can be extended even to the complex integers

Step-by-step explanation:

8 0
2 years ago
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(a) How many integers in the range 1 through 120 are integer multiples of 2, 3, or 5? keyboard_arrow_down Solution (b) How many
Umnica [9.8K]

Answer:

(a) 88 integers

(b) 92 integers

Step-by-step explanation:

(a) integers whose last digits are divisible by 2 are multiples of two or numbers whose digits ends with zero. So for number 1-120 , all the even numbers which are sixty in number are are multiples of two.

For  3, numbers whose digits sum is divisible by three are multiples of three. 3,6,9,12,15,18,21,24,27,30 are multiples of three from numbers 1-30. we have four 30s in 120. which means numbers of integers will be 10*4 = 40integers. However out of these numbers , half are also integers of 2 which reduces the number added to 20integers.

For 5, numbers whose digits ends with 5 or 0 are multiples of 5. this gives us 24 integers for 1-120. but out of these 24integers, 16 are common integers of 2 and 3 which reduces the number added to 8integers.

Thus from 1-120 the intergers of 2,3 or 5 = 60+20+8 = 88integers.

(b) if we are considering from numbers 1-140;

for 2 we wil have 70 integers,

for 5 we will have 28 integers, but those integers that end with 0 are also integers of 2 which reduces the number added to 14.

For 7, numbers 7,14,21,28,35,42,49,56,63,70 are multiples of three from 1-70. This pattern is repeated from number 71-140. hence we have 20 integers in all. However 12 of the multiples are also multiples of either 2 or 5 which reduces the number to 8 integers.

Thus from 1-140, the integers of 2, 5, or 7 = 70+14+8 = 92integers

3 0
3 years ago
Round this decimal!<br><br> 0.4944
Otrada [13]

1) 0.494

2) 0. 49

3) 0.5

7 0
3 years ago
How do you add add fraction with a different denominator?
kenny6666 [7]

Find the LCM (least common multiple) of the denominators, and use that as the denominator for the two fractions.

Ex.

\frac{3}{4} +\frac{2}{3}

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3 0
3 years ago
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Which property does each equation demonstrate?
abruzzese [7]

Answer:

it demonstartes a algebraic property

Step-by-step explanation:

3x#

=8=9=

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8 0
3 years ago
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