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4 years ago

-24+15-6=x

Mathematics

2 answers:

jek_recluse [69]4 years ago

5 0

Answer:

idk to be honest

Step-by-step explanation:

plz help a sis out im rlly just trying to get the points to do my stupid homwork, feel free to do the same things on my quetions

suter [353]4 years ago

4 0

Answer:

x = -15

Step-by-step explanation:

-24 + 15 - 6 = x

-9 - 6 = x

-15 = x

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Compute the following volume and surface area.

Vesnalui [34]

The surface area of rectangular solid is 208 square centimeter

The volume of rectangular solid is 192 cubic centimeter

<h3><u>Solution:</u></h3>

Given that rectangular solid has sides of 4 cm, 6 cm, and 8 cm

To find: surface area and volume of rectangular solid

Length = l = 4 cm

Width = w = 6 cm

Height = h = 8 cm

<h3><em><u>The formula to find the surface area of a rectangular prism is:</u></em></h3>

Surface Area = 2wl + 2lh + 2hw

where w is the width, the l is the length, and the h is the height.

$\text {surface area }=2(4 \times 6)+2(4 \times 8)+2(8 \times 6)\\\\\text {surface area } = 2(24) + 2(32) + 2(48)\\\\\text {surface area } = 48 + 64 + 96 = 208$

Thus the surface area of rectangular solid is 208 square centimeter

<h3><em><u>The formula for volume of rectangular solid is:</u></em></h3>

$Volume = Length \times Height \times Width$

$volume = 4 \times 6 \times 8 = 24 \times 8 = 192$

Thus the volume of rectangular solid is 192 cubic centimeter

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3 years ago

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3 years ago

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mamaluj [8]

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3 years ago

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What is the linear function equation that best fits the data set?

slavikrds [6]

Answer:

Option 3

Step-by-step explanation:

Given data set is,

{(1.5, 1), (2.5, 3), (3, 3), (3, 5), (3.5, 5), (4.5, 7), (5, 7), (5, 9), (5.5, 9), (6.5, 11), (7.5, 13)}

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3 years ago

Can anyone do question 25 part c? :)

inna [77]

$\begin{cases}x^3\qquad\qquad\ \ \ when\ x\geq3\\5\qquad\qquad\quad \ when\ 0\ \textless \ x\ \textless \ 3\\x^2-x+2\quad\ when\ x\leq0 \end{cases}\\\\\\ (a)\\ f(0)\iff x=0\implies f(x)=x^2-x+2\\\\f(0)=0^2-0+2=2\\\\(b)\\ \{f(2)\iff x=2;\ \ f(1)\iff x=1\}\implies f(x)=5\\\\ f(2)=5\quad\wedge\quad f(1)=5\\\\ f(2)-f(1)=5-5=0$

$(c)\\ \big\forall \limits_{ n\in R}\ n^2\geq 0\ \ \Rightarrow\ \ \big\forall \limits_{ n\in R}\ (-n^2)\leq 0 \ \ \Rightarrow\ \ x\leq0\ \ \Rightarrow\ \ f(x)=x^2-x+2\\\\f(-n^2)=(-n^2)^2-(-n^2)+2=n^4+n^2+2$

5 0

4 years ago