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Anna71 [15]
3 years ago
10

Can u help me solve this problem

Mathematics
2 answers:
iris [78.8K]3 years ago
7 0

Answer:

1

Step-by-step explanation:

Use PEMDAS:

Divide before adding and subtracting.

9-3/(1/3)+1\\\rightarrow 3/(1/3)=9\\9-9+1\\0+1\\\boxed {1}

<em>Brainilest Appreciated! </em>

topjm [15]3 years ago
3 0

Answer:

1

Step-by-step explanation:

9-3÷1/3+1=

1) 3÷1/3

3*3

9

2) 9-9+1

3)1

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There are 2 green pens, 3 blue pens, 4 red pens, and 1 black pen in the teachers desk. The teacher selects 2 pens at random, and
MAXImum [283]

Answer:

2/15

Step-by-step explanation:

2 green pens, 3 blue pens, 4 red pens, and 1 black pen =10 pens

P(red) = red/total = 4/10 = 2/5

Keep the pen

2 green pens, 3 blue pens, 3 red pens, and 1 black pen =9 pens

P(red) = red/total = 3/9 = 1/3

P(red,red) = 2/5 * 1/3 = 2/15

3 0
3 years ago
If anyone could plz help ill really appreciate it
Flura [38]

Answer:

Help with what is it mental help? Or no cause I’ve dealt with that a lot

Step-by-step explanation:

3 0
3 years ago
If anyone knows this please help me
alexgriva [62]

Answer:

oh hey I gotchu-

first of all you are gonna make that into two rectangle by slicing the top off if that makes sense so you now have a large rectangle (11×12) and a small one (3×8) now you use the area formula for rectangles base×height so the small one becomes (3×8)=24 and the large one is (11×12)=132. now to make them into one shape for the total area you add those two values 132+24=156 so your total area is 156m²

6 0
3 years ago
There are 18 women and 20 men in a room. Of the women, 10 are older than 35 years old. Of the men, 9 are older than 35 years old
Vinvika [58]
Answer: 50%

Step 1 add 18+20 = 38

Step 2 add 10+9= 19

Step 3 divide 19 by 38 = 2

So if would be half which is equal to 50%

7 0
3 years ago
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
3 years ago
Read 2 more answers
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