Find 174.2% of 72.Round to the nearest hundredth.

I need to show my work, could anyone help? (need by tonight 3/10/20

marishachu [46]

Answer:

14 gallons....$42

Step-by-step explanation:

The car requires one gallon every 32 miles...

The car requires c gallons for 448 miles

c = 448 × 1 / 32

= 14 gallons..

One gallon = $3

Fourteen gallons = ??

14 × 3 / 1 = $42

3 0

3 years ago

Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen

Jobisdone [24]

Parameterize $S$ by the vector function

$\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k$

so that the normal vector to $S$ is given by

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}$

In this case, the normal vector is

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k$

with magnitude $\sqrt{1^2+2^2+1^2}=\sqrt6$ . The integral of $f(x,y,z)=e^z$ over $S$ is then

$\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx$

where $T$ is the region in the $x,y$ plane over which $S$ is defined. In this case, it's the triangle in the plane $z=0$ which we can capture with $0\le x\le8$ and $0\le y\le\frac{8-x}2$ , so that we have

$\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}$

5 0

3 years ago

Can some one please explain this to me

bezimeni [28]

Make me the brilranest.thankyou.i hope it was helpful

5 0

2 years ago

Read 2 more answers

The point P = (-3, y) lies on the unit circle shown below. What is the value of y

alukav5142 [94]

The equation of the circle is given as (x-h)² + (y-k)² = r². Then the value of y will be ± √5/3.

<h3>What is an equation of a circle?</h3>

A circle can be characterized by its center's location and its radius's length.

Let the center of the considered circle be at (h, k) coordinate.

Let the radius of the circle be 'r' units.

Then, the equation of that circle would be:

(x-h)² + (y-k)² = r²

The equation of the circle has the center at the origin and the radius is one unit. Then we have

x² + y² = 1

The point P = (-2/3, y) lies on the unit circle. Then the value of y will be

(-2/3)² + y² = 1

y² = 1 - 4/9

y² = 5/9

y = ± √5 / 9

Learn more about the equation of a circle here:

brainly.com/question/10165274

#SPJ1

5 0

2 years ago

Find the center and radius of the circle.<br> (x + 3)2 + (y + 4)2 =9

Tpy6a [65]

The general equation for any circle with its center at point (a, b) is

(x - a)² + (y - b)² = (radius)²

So the circle in the question is centered at (-3, -4), and its radius is 3 .

7 0

3 years ago