Question

In the deep space between galaxies, the density of atoms is as low as 106 atoms/m3, and the temperature is a frigid 3.0 K. What is the pressure?

Answer 1

Answer:

$4.388*10^-^2^1$

Explanation:

Given:

$N/V= 106 atoms/m^3$

$T=3.0K$

we know the values of

$K_{b} =1.38*10^-^2^3 J/K$

$N_{A} =6.02*10^2^3/mol$

Formula:

$PV=NK_{b} T$

rearranging the formula and substituting values

$P=(NK_{b} T)/V$

$P=(106)(1.38*10^-^2^3)(3)$

$P=4.388 *10^-^2^1 Pa$