Ead sulfide + oxygen lead oxide + sulfur dioxide
2 PbS(s) + 3 O2(g) 2 PbO(s) + 2 SO2<span>(g)
Hope this is what you are asking for :))</span>
Assuming that the percentage composition is on the basis of weight percentage, therefore the mass of lithium would simply be the product of the two, that is:
mass Lithium = 0.188 * 1.70 g
mass Lithium = 0.3196 g = 0.32 g
Answer:
n = 0.0102 mol.
Explanation:
Hello there!
In this case, according to the ideal gas law, which allows us to set up a relationship among volume, pressure, temperature and moles, we can define it as:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
Thus, given the volume in liters (0.1000 L), temperature in kelvins (298.15 K) and pressure in atmospheres (2.50 atm), we can solve for moles as shown below:
![n=\frac{PV}{RT}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7BPV%7D%7BRT%7D)
Thereafter, we plug in the aforementioned values to obtain:
![n=\frac{2.50atm*0.1000L}{0.08206\frac{atm*L}{mol*K}*298.15K}\\\\n=0.0102mol](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B2.50atm%2A0.1000L%7D%7B0.08206%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A298.15K%7D%5C%5C%5C%5Cn%3D0.0102mol)
Best regards!