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Ghella [55]
3 years ago
11

A business has $15,000 to spend on airline tickets to travel to a conference. It wants 27 of its employees to attend. The busine

ss wants to buy as many business-class seats as possible. The business-class seats cost $700. The economy-class seats cost $375. How many of each type of ticket should the business purchase?
11 business class and 16 economy class

12 business class and 15 economy class

15 business class and 12 economy class

16 business class and 11 economy class
Mathematics
2 answers:
son4ous [18]3 years ago
6 0

Answer:

In order to get as many tickets they need 15 business class tickets and 12 economy class tickets (700x15=10,500)(375x12=4500) Which when you add those two makes 15,000.

Step-by-step explanation:

VikaD [51]3 years ago
4 0
In order to get as many tickets they need 15 business class tickets and 12 economy class tickets (700x15=10,500)(375x12=4500) Which when you add those two makes 15,000.
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Yi Ting weighs 8.3 kg kilograms her older brother is four times as heavy as Yi Ting how much does her older brother weigh in kil
dexar [7]
8.3*4 = 33.2 kg.
Hopefully that is correct
Since Yi Ting weighs 8.3 and her brother is 4 times heavier you would multiply those two numbers to get the answer.
3 0
3 years ago
a cell phone battery uses 1/3 of its charge in 3/8 of a day. How much charge will it use in one day?​
brilliants [131]

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3 0
3 years ago
A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time).
likoan [24]

Answer:

(a). 72.9%.

(b). 13.6 hr.

Step-by-step explanation:

So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;

=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "

=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"

So, we will be making use of the Crawford learning curve model.

T(7) + 10 = T (17) = 30 min.

T(7) = T1(7)^b = 45.

T(17 ) = T1(17)^b = 30.

(T1) = 45/7^b = 30/17^b.

45/30 = 7^b/17^b = (7/17)^b.

1.5 = (0.41177)^b.

ln 1.5 = b ln 0.41177.

0.40547 = -0.8873 b.

b = - 0.45696.

=> 2^ -0.45696 = 0.7285.

= 72.9%.

(b). T1= 45/7^ - 045696 = 109.5 hr.

V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .

V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .

= 815.7 min .

= 13.595 hr.

8 0
3 years ago
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sammy [17]
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5 0
3 years ago
An experiment is to be conducted using environmentally safe peppermint oil to study the effectiveness of deterring mice from inf
shutvik [7]

Answer:

Option E is correct.

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Step-by-step explanation:

The treatments in this type of statistical experiment refers to the part of the experiment that is tweaked, controlled or varied in the cases being studied. In this experiment, the method of essential oil dispersal is what is varied in the two experimental cases of this study.

Experimental Unit refers to the subject matters, who are participants in the experiment. They are the ones that the effect of the treatments is tested upon.

For this study, the experimental units are the mice subjected to either of the two methods of peppermint oil dispersal.

The response variable is how the experimental units (participants) respond to the treatments (experimental tweaks). Or how the tweaks manifest observable results in the participants of the study. For this study, the effect of the tweaks in the mice is shown in the number of mice that remain in each dwelling (where the two methods of peppermint oil dispersal have been implemented). Hence, the response variable is the number of mice in each dwelling.

Hope this Helps!!!

5 0
3 years ago
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