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Ghella [55]
3 years ago
11

A business has $15,000 to spend on airline tickets to travel to a conference. It wants 27 of its employees to attend. The busine

ss wants to buy as many business-class seats as possible. The business-class seats cost $700. The economy-class seats cost $375. How many of each type of ticket should the business purchase?
11 business class and 16 economy class

12 business class and 15 economy class

15 business class and 12 economy class

16 business class and 11 economy class
Mathematics
2 answers:
son4ous [18]3 years ago
6 0

Answer:

In order to get as many tickets they need 15 business class tickets and 12 economy class tickets (700x15=10,500)(375x12=4500) Which when you add those two makes 15,000.

Step-by-step explanation:

VikaD [51]3 years ago
4 0
In order to get as many tickets they need 15 business class tickets and 12 economy class tickets (700x15=10,500)(375x12=4500) Which when you add those two makes 15,000.
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Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
lubasha [3.4K]

Answer:

The answer is option C.

<h3>-6, -5 2/5, -4 1/5</h3>

Step-by-step explanation:

The arithmetic sequence is given by

A(n) =  - 6 + (n - 1)( \frac{1}{5} )

where n is the number of terms

<u>For</u><u> </u><u>the</u><u> first</u><u> </u><u>term</u>

n = 1

So we have

A(1) =  - 6 + (1 - 1)( \frac{1}{5} )

=  - 6 + (0)( \frac{1}{5} )

=  - 6

<u>For</u><u> </u><u>the</u><u> </u><u>fou</u><u>rth</u><u> term</u>

n = 4

A(4) =  - 6 + (4 - 1)( \frac{1}{5} )

=  - 6 + (3)( \frac{1}{5} )

=  - 5 \frac{2}{5}

<u>For</u><u> </u><u>the</u><u> </u><u>tenth</u><u> </u><u>term</u>

n = 10

A(10) =  - 6 + (10 - 1)( \frac{1}{5} )

=  - 6 + (9)( \frac{1}{5} )

=  - 4 \frac{1}{5}

Hope this helps you

4 0
3 years ago
Can someone please help me solve this? and explain how you got the answer? Thank you​
Tatiana [17]
36.9
it might be wrong but at least i tried
5 0
3 years ago
A line has slope 5/6 and y-intercept-3
viva [34]

Answer:

The equation would be y = 5/6x - 3

Step-by-step explanation:

8 0
3 years ago
​You need to wrap a present that you will put inside a cylindrical container. You’ll need to know how much will fit in the conta
nirvana33 [79]

Answer:

149.28 sq. inches

137.5 cubic inches.

Step-by-step explanation:

The cylindrical container has length or height (h) 7 inches and has a diameter of 5 inches i.e. radius (r) 2.5 inches.

Now, total surface area of the container = 2\pi r^{2} + 2\pi rh

= \frac{2 \times 22 \times (2.5)^{2} }{7} + \frac{2 \times 22 \times 2.5 \times 7}{7}

= 39.28 + 110  

= 149.28 sq. inches (Answer)

Again the volume of the container will be \pi r^{2}h

= \frac{22 \times (2.5)^{2} \times 7}{7}

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3 years ago
Prove:<br> sin^2x (sec^2x + csc^2x)=sec^2x
Vikki [24]
Sin^2x (sec^2x + csc^2x) = sec^2x

I would convert the functions in the parentheses to their reciprocals.

sin^2x (1/cos^2x + 1/sin^2x) = sec^2x

Now distribute the sine.

sin^2x/cos^2x + sin^2x/sin^2x = sec^2x

Remember that sine divided by cosine is always tangent.

tan^2x + sin^2x/sin^2x = sec^2x

The remaining fraction is simply 1.

tan^2x + 1 = sec^2x

Use the Pythagorean identity to add the left side.

sec^2x = sec^2x

Q.E.D.
4 0
3 years ago
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