To get the answer to this equation you first cancel out the 6! ;)
(x^2-1)(6x-1) / (x+1)
Then rewrite x^2-1 in the form a^2 + b^2, where a=x and b=1
(x^2-1^2)(6x-1) / (x+1)
Then use the difference of squares!
(x+1)(x-1)(6x-1) / (x+1)
LASTLY cancel "x+1" !
so ur answer is (x-1) (6x-1)
That makes the correct answer to this problem answer choice (D) (x-1) (6x-1)
YW!!! ;)
Answer:
h(x-1)=4x-7
Step-by-step explanation:
Given :
h(x)=4x-3
Now,
putting the value of x =x-1
h(x-1)=(4(x-1)-3)
h(x-1)=4x-4-3
h(x-1)=4x-7
Answer will be h(x-1)=4x-7
In a standard shuffled deck of 52 cards, half of the cards are black and half of the cards are red: (26 black cards, 26 red cards).
Since we are interested in pulling a black card first, the probability is 26/52.
Without replacing the card we have chosen, we are left with 51 total cards in the entire deck (25 black cards, 26 red cards).
Now that we want to pull a red card, we know that the probability will be 26/51.
Since we are interested in both events occurring simultaneously, we must multiply the probability of the first by the probability of the second, aka: (26/52) * (26/51)
The answer we are given is 0.2549
The code at the end will be LEAP YEAR
you can use that to figure it out
