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drek231 [11]
3 years ago
15

You select a card from a standard shuffled deck of 52 cards. Without replacing, you select another card. Find the probability th

at you select a black card, then a red card.
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
8 0

In a standard shuffled deck of 52 cards, half of the cards are black and half of the cards are red: (26 black cards, 26 red cards).

Since we are interested in pulling a black card first, the probability is 26/52.

Without replacing the card we have chosen, we are left with 51 total cards in the entire deck (25 black cards, 26 red cards).

Now that we want to pull a red card, we know that the probability will be 26/51.

Since we are interested in both events occurring simultaneously, we must multiply the probability of the first by the probability of the second, aka: (26/52) * (26/51)

The answer we are given is 0.2549

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How many spaces to the right of a number line is 3.25
pochemuha

Answer:

3.25 spaces, but you need to tell me how big the spaces are

8 0
3 years ago
E-Z View cable company charges a flat rate of $40 per month for service and $4.95 for each pay per view movie. View the Best cha
Sliva [168]
The difference between the first company and the other is that the first charges $1 less per movie than the second , but charges $15 more than the second as well.
To awnser this problem and equal the charges in bth companies we just need to cancel out the $15 the first company charges more than the second.
As we pay more $1 each movie in the first , we would need to view 15 movies to equalize the charges from both companies :
x= 15 if we want to equalize the charges

f(x) = 4.95(15) + 40
f(x) = 74.25 + 40 = 114.25

g(x) = 5.95(15) + 25
g(x) = 89.25 + 25 = 114.25

Awnser: We would need to view 15 pay per view to equalize the bills from both companies

6 0
4 years ago
Read 2 more answers
What would the variables for a and b be? 3/x + 5/x^2 = (ax+b)/x^2
allsm [11]

Answer:

a=3,b=5

Step-by-step explanation:

\frac{3}{x}  +  \frac{5}{ {x}^{2}  }  \\  =  \frac{3x}{ {x}^{2} }   +  \frac{5}{ {x}^{2} }  \\  =  \frac{3x + 5}{ {x}^{2} }

so as you got it:

\frac{(ax + b)}{ {x}^{2} }  =  \frac{3x + 5}{ {x}^{2} }  \\ a = 3 \\ b = 5

4 0
3 years ago
Simplify the following expression: 2x-2y+5z-2x-y+3z. A.x-3y+8z. B.2x-2y+8z. C.3y+8z. D.-3y+8Z Plzzzzzzzz help
Sergeu [11.5K]
Hello there ^ _ ^

2x - 2y + 5z - 2x - y + 3z
The first thing you need to do is to put all the common terms together.

2x - 2x - 2y - y + 5z + 3z
2x - 2x = 0 or nothing so we don't need to put that in the solution
-3y + 8z

The correct option is D



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3 0
3 years ago
You are an assistant director of the alumni association at a local university. You attend a presentation given by the university
NNADVOKAT [17]

Answer:

(0.102, -0.062)

Step-by-step explanation:

sample size in 2018 = n1 = 216

sample size in 2017 = n2 = 200

number of people who went for another degree in 2018 = x1 = 54

number of people who went for another degree in 2017 = x2 = 46

p1 = x1/n1 = 0.25

p2 = x2/n2 = 0.23

At 95% confidence level, z critical = 1.96

now we have to solve for the confidence interval =

<h2> p1 -p2 ± z*\sqrt{((1-p1)*p1)/n1 + ((1-p2)*p2/n2}</h2>

0.25 -0.23 ± 1.96*\sqrt{((1 - 0.25) * 0.25)/216 + ((1 - 0.23) *0.23/200}

= 0.02 ± 1.96 * 0.042

= 0.02 + 0.082 = <u>0.102</u>

= 0.02 - 0.082 = <u>-0.062</u>

<u>There is 95% confidence that there is a difference that lies between  - 0.062 and 0.102 on the proportion of students who continued their education in the years, 2017 and 2018.</u>

<u></u>

<u>There is no significant difference between the two.</u>

5 0
3 years ago
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