What does (4v+16v^2) equal to ?

Mathematics

1 answer:

crimeas [40]3 years ago

8 0

Answer:

4v(4v+1)

Step-by-step explanation:

(4v+16v^2)

=16vv+4v

=4*4vv+4v

=4v(4v+1)

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hram777 [196]

Answer:

D: x < 20

Step-by-step explanation:

-4x + 16 > -64

subtract 16 from both sides because you must isolate x.

-4x + 16 - 16 > -64 - 16

-4x > -80

Then divide -4 on both sides... I believe that when you divide a number by a negative number you must flip the sign...

-4x/ -4 < -80/ -4

x < 20

(negative divided by a negative will result in a POSITIVE.)

Hope this helped... I truly apologize if this is wrong..

3 0

2 years ago

Solve for x. Sqrt8 (Sqrt2 - x) = 11

Alexus [3.1K]

Answer: $\frac{-7\sqrt{2} }{4}$

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get $\sqrt{16}-x\sqrt{8} =11$ . We know that the square root of 16 is ±4, so now our equation is ±4 - $x\sqrt{8}$ =11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - $x\sqrt{8}$ =11. We can use inverse operations to make the a little easier to solve: -7= $x\sqrt{8}$ . We divide both sides by $\sqrt{8}$ to get $\frac{-7}{\sqrt{8} } =x$ , which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by $\frac{\sqrt{8} }{\sqrt{8} }$ (which is equal to one so we can use it) which is equal to $\frac{-7\sqrt{8} }{8}$ . Let's finish this by simplifying it. $\sqrt{8} =2\sqrt{2}$ (2x $2^{2}$ ). We can simplify it further by simplifying the 2, making it $\frac{-7\sqrt{2} }{4}$ .