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bonufazy [111]
4 years ago
15

Which decimal is equivalent to 13/11

Mathematics
2 answers:
TiliK225 [7]4 years ago
7 0

Answer:

1.18 is the answer but if u want to round u have the answer as 1.20=1.2

Step2247 [10]4 years ago
6 0

Answer:

The answer is approximately 1.2.

Step-by-step explanation:

The actual answer is 1.18181818182, but when you round you get 1.2

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Number 4 please!!!!!
Kazeer [188]

Answer:9787987987987987899999999888888888888888888'

Step-by-step explanation:

that that that 14523095480239845023984203984230482309423094823029834

8 0
3 years ago
What is the arithmetic mean of the following numbers? 69,93,72,83,57,69,92
Rama09 [41]

Answer:

69

Step-by-step explanation:

3 0
3 years ago
5. Point H is located at (-7, 5). Where is H' after a 270° clockwise rotation?​
scZoUnD [109]

I hope this helps you sorry to get it wrong

Answer:

H after a 270 degrees clockwise rotation is at  (-5,-7)

7 0
3 years ago
A cylindrical container contains some sand. If the diameter of the container is 10 inches and its height is 3 inches, about how
Mazyrski [523]

Answer:

251.33in²

Step-by-step explanation:

A cylindrical container contains some sand. If the diameter of the container is 10 inches and its height is 3 inches, about how much sand fits inside the container?

We solve the above question using the formula for Total surface area of a cylinder.

TSA = 2πr (h + r) Square units.

Where

h = Height of the cylinder

r = Radius of the cylinder

Diameter of the container is 10 inches

Hence, radius = Diameter/2 = 10/2 = 5 inches

Height is 3 inches.

Hence, Total surface area =

2 × π × 5 (5 + 3)

= 10π × (8)

= 251.32741229 in²

Approximately = 251.33 in²

Therefore, the amount of sand that can fit into the cylinder = 251.33 in²

6 0
3 years ago
Research suggests that about 60% of CSU graduates started at a community college. In random samples of 100 CSU graduates, the pe
Nesterboy [21]

Answer:

The probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

The information provided is:

<em>p</em> = 0.60

<em>n</em> = 100

As <em>n</em> = 100 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample proportions.

The distribution of sample proportion is \hat p\sim N(0.60, 0.049^{2}).

Compute the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% as follows:

P(|\hat p-\mu_{\hat p}|=0.05)=P(-0.05

                             =P(\frac{-0.05}{0.049}

Thus, the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.

8 0
3 years ago
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