The product of something means multiplying the terms together.
(2x+3) (4x^2-5x+6)
Secondly you need to distribute the terms to each other (Think of problems like FOIL)
2x * 4x^2 + 2x(-5x) + 2x * 6 + 3 * 4x^2 + 3(-5x) + 3 * 6
Then you must take into account that some of the numbers are negative. (minus-plus rules!)
2x * 4x^2 - 2x * 5x + 2x * 6 + 3 * 4x^2 - 3 * 5x + 3 * 6
Now is the tricky part of simplifying everything.
2x * 4x^2 = 8x^3
2x * 5x = 10x^2
2x * 6 = 12x
3 * 4x^2 = 12x^2
3 * 5x = 15x
3 * 6 = 18
8x^3 - 10x^2 + 12x + 12x^2 - 15x + 18
Then you group like terms.
8x^3 - 10x^2 + 12x^2 - 3x + 18
8x^2 + 2x^2 - 3x + 18
The trickiest part of this is distributing all of the terms within the parentheses, once you've done that, it's smooth sailing!
The anser is that what i think
3) 3(8b + 3)
4) 57
I’m pretty sure that this is the answer
Let the two numbers be represented by x and y. The problem statement gives rise to two sets of equations.
x - y = 0.6
y/x = 0.6 . . . . . . . assuming x is the larger of the two numbers
or
x/y = 0.6 . . . . . . . assuming y has the larger magnitude
The solution of the first pair of equations is
(x, y) = (1.5, 0.9)
The solution of the first and last equations is
(x, y) = (-0.9, -1.5)
The pairs of numbers could be {0.9, 1.5} or {-1.5, -0.9}.
Answer:
square root of 7
Step-by-step explanation:
2 times 2 is 4
3 times 3 is 9
7 is the only option between 4 and 9
(this was more the easy method lol but hope this helps)
