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inn [45]
3 years ago
8

In the rectangle below, AE = 3x+7, CE = 5x-7, and m Find BE and m

Mathematics
1 answer:
Alborosie3 years ago
3 0

Answer:

AE-3*x+7=0 and CE=5*x-7

Step-by-step explanation:

-3*x and -7 move these terms to the left it becomes AE-3*x-7=0 do the same step that you did with the first one.

You might be interested in
A country will produce 3000 missiles this year. Each of the short-range missiles cost $200000 to produce. Each of the medium-ran
Lynna [10]

Answer:

$350,000

Step-by-step explanation:

Let's define:

  • s: amount of short-range missiles produced
  • m: amount of medium-range missiles produced
  • l: amount of long-range missiles produced

From the total production and the ratios we can write the following equations:

s + m + l = 3000

s/m = 3/3 = 1 = m/s

s/l = 3/4 or l/s = 4/3

Dividing the first equation by s, we get:

s/s + m/s + l/s = 3000/s

1 + 1 + 4/3 = 3000/s

10/3 = 3000/s

s = 3000*3/10 = 900

m = 900

l =  4/3*900 = 1200

From the money that the countries plans to use and each missile cost, we can write the following equation:

200,000*s + 300,000*m + cost*l = 870,000,000

Replacing with previous result:

200,000*900 + 300,000*900 + cost*1200 = 870,000,000

cost = (870,000,000 - 200,000*900 - 300,000*900)/1200 = 350,000

3 0
3 years ago
32% of a number is 64 what is the number
Serjik [45]

Answer:

If you take 32 percent of a number and get 64, then what is that number? In other words, you know that 32 percent of a number is 64 and you want to know what that initial number is. Therefore, the answer to "64 is 32 percent of what number?" is 200, and you can also derive that 32 percent of 200 equals 64.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Simplify the following expression.<br> 343 1/3<br> (Write your answer as an integer.)
aalyn [17]
343^1/3
=(7)^3*1/3 [ 3 and 3 are cancelled]
=7
4 0
3 years ago
In tossing four fair dice, what is the probability of tossing, at most, one 3
11Alexandr11 [23.1K]

<u>Answer- </u>

In tossing four fair dice, the probability of getting at most one 3 is 0.86.

<u>Solution-</u>

The probability of getting at most one 3 is, either getting zero 3 or only one 3.

P(A) =The \ probability \ of \ getting \ zero \ 3 =(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})=\frac{625}{1296} =0.48                    ( ∵ xxxx )

P(B) = The \ probability \ of \ getting \ only \ one \ 3 =(4)(\frac{1}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6}) = 0.38                    ( ∵ 3xxx, x3xx, xx3x, xxx3 )

P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86

7 0
3 years ago
1. (2 points) Solve each equation and write the answer on the line
BARSIC [14]
Eighteen tens < 21 × (5+5)

Hope this helps!
7 0
4 years ago
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